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anonymous

  • one year ago

A particle moving uniformly along the x axis is located at 9.27 m at 1.12 s and at 4.6 m at 3.04 s. Find its displacement during this time interval.

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  1. kropot72
    • one year ago
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    The particle moves from right to left, therefore we have negative displacement, given by: -(9.27 - 4.6)m

  2. anonymous
    • one year ago
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    Ok, so that means the answer is -4.67.

  3. kropot72
    • one year ago
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    You are correct.

  4. anonymous
    • one year ago
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    Yey:) and if they ask for velocity, then would i just find the slope? Like: (9.27-4.6)/(1.12-3.04)

  5. anonymous
    • one year ago
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    And would avg. speed be the same as velocity for this question?

  6. kropot72
    • one year ago
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    Velocity is a vector quantity. Therefore it is given by: \[\large v=\frac{-4.67}{(3.04-1.12)}\ m/s\]

  7. anonymous
    • one year ago
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    Ohh, I see. thank you!

  8. kropot72
    • one year ago
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    You're welcome :)

  9. anonymous
    • one year ago
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    How about average speed? Would the average speed differ from the velocity?

  10. kropot72
    • one year ago
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    Speed is a scalar quantity, therefore the negative sign does not apply.

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