## anonymous one year ago A particle moving uniformly along the x axis is located at 9.27 m at 1.12 s and at 4.6 m at 3.04 s. Find its displacement during this time interval.

1. kropot72

The particle moves from right to left, therefore we have negative displacement, given by: -(9.27 - 4.6)m

2. anonymous

Ok, so that means the answer is -4.67.

3. kropot72

You are correct.

4. anonymous

Yey:) and if they ask for velocity, then would i just find the slope? Like: (9.27-4.6)/(1.12-3.04)

5. anonymous

And would avg. speed be the same as velocity for this question?

6. kropot72

Velocity is a vector quantity. Therefore it is given by: $\large v=\frac{-4.67}{(3.04-1.12)}\ m/s$

7. anonymous

Ohh, I see. thank you!

8. kropot72

You're welcome :)

9. anonymous

How about average speed? Would the average speed differ from the velocity?

10. kropot72

Speed is a scalar quantity, therefore the negative sign does not apply.