## anonymous one year ago Can someone help me with this cube roots question?

1. BloomLocke367

I can try :)

2. anonymous

3. anonymous

I know you have to substitute in the values, but I can't figure out how to simplify to get a whole number. We haven't done imaginaries yet so I know I can't use those.

4. BloomLocke367

What do you mean you can't figure out how to simplify to get a whole number?

5. BloomLocke367

You know what a cubed number is, right?

6. anonymous

All the values in the example questions are getting whole numbers for y. I don't know how when they aren't perfect cubes.

7. anonymous

Yes

8. BloomLocke367

They are perfect cubes >.<

9. anonymous

I'm not sure what to do then

10. BloomLocke367

And take a look at that first one you did. You made a small mistake.

11. BloomLocke367

How did you get 1?

12. anonymous

Oh wait is it -1?

13. BloomLocke367

$\sqrt[3]{-1}=-1$ and then you also have to subtract 2 from that. $$-1-2=?$$

14. anonymous

Oops, -3.

15. anonymous

Then how do I find the cube root of -3?

16. BloomLocke367

you don't need to find the cube root of -3. Now that you have -3, all that it means is that $-3=\sqrt[3]{-1}-2$

17. BloomLocke367

so -3 is your y-value. The only thing you need to take the cube root of is the x-value that was given to you

18. anonymous

So the next one would be -2?

19. BloomLocke367

Yes! $$\Huge\color{lime}{\checkmark}$$

20. anonymous

Then 0, then 2?

21. BloomLocke367

Yep!

22. anonymous

Thank you so much!!

23. BloomLocke367

You're welcome! I'm glad I was able to help :)