anonymous
  • anonymous
Can someone help me with this cube roots question?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
BloomLocke367
  • BloomLocke367
I can try :)
anonymous
  • anonymous
anonymous
  • anonymous
I know you have to substitute in the values, but I can't figure out how to simplify to get a whole number. We haven't done imaginaries yet so I know I can't use those.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

BloomLocke367
  • BloomLocke367
What do you mean you can't figure out how to simplify to get a whole number?
BloomLocke367
  • BloomLocke367
You know what a cubed number is, right?
anonymous
  • anonymous
All the values in the example questions are getting whole numbers for y. I don't know how when they aren't perfect cubes.
anonymous
  • anonymous
Yes
BloomLocke367
  • BloomLocke367
They are perfect cubes >.<
anonymous
  • anonymous
I'm not sure what to do then
BloomLocke367
  • BloomLocke367
And take a look at that first one you did. You made a small mistake.
BloomLocke367
  • BloomLocke367
How did you get 1?
anonymous
  • anonymous
Oh wait is it -1?
BloomLocke367
  • BloomLocke367
\[\sqrt[3]{-1}=-1\] and then you also have to subtract 2 from that. \(-1-2=?\)
anonymous
  • anonymous
Oops, -3.
anonymous
  • anonymous
Then how do I find the cube root of -3?
BloomLocke367
  • BloomLocke367
you don't need to find the cube root of -3. Now that you have -3, all that it means is that \[-3=\sqrt[3]{-1}-2\]
BloomLocke367
  • BloomLocke367
so -3 is your y-value. The only thing you need to take the cube root of is the x-value that was given to you
anonymous
  • anonymous
So the next one would be -2?
BloomLocke367
  • BloomLocke367
Yes! \(\Huge\color{lime}{\checkmark}\)
anonymous
  • anonymous
Then 0, then 2?
BloomLocke367
  • BloomLocke367
Yep!
anonymous
  • anonymous
Thank you so much!!
BloomLocke367
  • BloomLocke367
You're welcome! I'm glad I was able to help :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.