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anonymous

  • one year ago

HELP ME The equation for finding the area of a triangle is A=1/2(b+c)h what is the equation solved for h.

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  1. Jhannybean
    • one year ago
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    to solve for h we're going to need to isolate h to one side of the equation. We have... \[\sf A= \frac{(b+c)h}{2}\] Let's start by distributing the h to both terms in the ()

  2. anonymous
    • one year ago
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    Mind if I work this out with you @Jhannybean or should I let this person try and work it out with you?

  3. Jhannybean
    • one year ago
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    Sure, you can try

  4. anonymous
    • one year ago
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    So I would first start by multiplying both sides by two- A(2) = (b + c) h

  5. Jhannybean
    • one year ago
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    Sure

  6. anonymous
    • one year ago
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    then I would subtract c from both sides- a(2) - c

  7. anonymous
    • one year ago
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    a(2) - c = b(h)

  8. Jhannybean
    • one year ago
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    yeah, no. that doesnt work.

  9. Jhannybean
    • one year ago
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    because now you have 2A = (b + c) \(\sf \color{red}{h}\) So you have to distribute h into all terms within the ( )

  10. anonymous
    • one year ago
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    but aren't we trying to figure out the formula for h?

  11. anonymous
    • one year ago
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    by distributing h, it would only make the problem more complex- yet you would get the same solution...right?

  12. Jhannybean
    • one year ago
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    Well, yes, it would make it more complex. You are right. then what you can do is treat (b+c) as ONE term, and then divide both sides of the equation by it.

  13. anonymous
    • one year ago
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    Exactly! So a(2) - (b+c) = h correct?

  14. Jhannybean
    • one year ago
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    \[\sf 2A=(b+c)h\]\[\sf h=\frac{2A}{b+c}\]

  15. anonymous
    • one year ago
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    Thank you guys

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