HELP ME The equation for finding the area of a triangle is A=1/2(b+c)h what is the equation solved for h.

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HELP ME The equation for finding the area of a triangle is A=1/2(b+c)h what is the equation solved for h.

Mathematics
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to solve for h we're going to need to isolate h to one side of the equation. We have... \[\sf A= \frac{(b+c)h}{2}\] Let's start by distributing the h to both terms in the ()
Mind if I work this out with you @Jhannybean or should I let this person try and work it out with you?
Sure, you can try

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So I would first start by multiplying both sides by two- A(2) = (b + c) h
Sure
then I would subtract c from both sides- a(2) - c
a(2) - c = b(h)
yeah, no. that doesnt work.
because now you have 2A = (b + c) \(\sf \color{red}{h}\) So you have to distribute h into all terms within the ( )
but aren't we trying to figure out the formula for h?
by distributing h, it would only make the problem more complex- yet you would get the same solution...right?
Well, yes, it would make it more complex. You are right. then what you can do is treat (b+c) as ONE term, and then divide both sides of the equation by it.
Exactly! So a(2) - (b+c) = h correct?
\[\sf 2A=(b+c)h\]\[\sf h=\frac{2A}{b+c}\]
Thank you guys

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