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anonymous
 one year ago
HELP ME
The equation for finding the area of a triangle is A=1/2(b+c)h what is the equation solved for h.
anonymous
 one year ago
HELP ME The equation for finding the area of a triangle is A=1/2(b+c)h what is the equation solved for h.

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Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1to solve for h we're going to need to isolate h to one side of the equation. We have... \[\sf A= \frac{(b+c)h}{2}\] Let's start by distributing the h to both terms in the ()

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mind if I work this out with you @Jhannybean or should I let this person try and work it out with you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I would first start by multiplying both sides by two A(2) = (b + c) h

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then I would subtract c from both sides a(2)  c

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1yeah, no. that doesnt work.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1because now you have 2A = (b + c) \(\sf \color{red}{h}\) So you have to distribute h into all terms within the ( )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but aren't we trying to figure out the formula for h?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0by distributing h, it would only make the problem more complex yet you would get the same solution...right?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1Well, yes, it would make it more complex. You are right. then what you can do is treat (b+c) as ONE term, and then divide both sides of the equation by it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Exactly! So a(2)  (b+c) = h correct?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1\[\sf 2A=(b+c)h\]\[\sf h=\frac{2A}{b+c}\]
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