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anonymous
 one year ago
Help MEDAL GIVEN !!!
anonymous
 one year ago
Help MEDAL GIVEN !!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The roots of the equation \[2x^2 + 5x  8 = 0\] are \[\alpha \] and \[\beta \]. Find the quadratic equations whose roots are : \[5\alpha + \frac{ 1 }{ \alpha }, 5\beta + \frac{ 1 }{ \beta } \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you found the sum and product of them?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\alpha+\beta = \frac{ 5 }{ 2 } \] , \[\alpha \beta = \frac{ 8 }{ 2 } = 4\] New sum = \[5\alpha + \frac{ 1 }{ \alpha } + 5\beta + \frac{ 1 }{ \beta } \] I don't know what to do now

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3well why not make it \[\frac{5\alpha^2 + 1}{\alpha} + \frac{5\beta^2 + 1}{\beta}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then you take the sum and product of that?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3then get the common denominator and add the numerators

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then for new product: \[(5\alpha + \frac{ 1 }{ \alpha })* (5\beta+\frac{ 1 }{ \beta })\] in the end I got the answer to be : \[8x^2 95  786\]. which I believe is wrong :( !!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then input the sum and product into \(\sf x^2 (\text{sum of roots})x +(\text{product of roots})=0\)?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3look at the sum of the roots this way \[5\alpha + 5 \beta = \frac{1}{\alpha} + \frac{1}{\beta} = 5(\alpha + \beta) + \frac{\alpha + \beta}{\alpha \beta}\] does that help

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3oops should read \[5 \alpha + 5 \beta + \frac{1}{\alpha} + \frac{1}{\beta}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh yes that does help very much .. cheers :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so was I correct then ????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what did you guys get as your final answer???

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.35(5/2) + (5/2)/4 = 100/8 + 5/8 = 95/8 so that seems correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about the product ... it seems way tooo big

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3as for the product I thought \[(5\alpha + \frac{1}{\alpha})(5\beta + \frac{1}{\beta} = 25\alpha \beta + \frac{5\alpha}{\beta} + \frac{5\beta}{\alpha} + \frac{1}{\alpha \beta}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3which becomes \[25 \alpha \beta + \frac{5 \alpha^2 + 5\beta^2}{\alpha \beta} + \frac{1}{\alpha \beta}\] or \[25 \alpha \beta + \frac{5[(\alpha + \beta)^2  2 \alpha \beta]}{\alpha \beta} + \frac{1}{\alpha \beta}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3so I think you need to be careful with the signs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0tooo confusing wht do you get as finl answer ???

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.3so if b/a = 95/8 then c/a = 32/8 so a = 8, b = 95 and c 32 that's my best guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got something else
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