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diamondboy

  • one year ago

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  1. diamondboy
    • one year ago
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    |dw:1442091361905:dw|

  2. diamondboy
    • one year ago
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    @Nnesha

  3. diamondboy
    • one year ago
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    @Jhannybean

  4. Jhannybean
    • one year ago
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    Oo...

  5. Jhannybean
    • one year ago
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    \[\sf u= x+3 \implies x=u-3\]

  6. Jhannybean
    • one year ago
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    \[\sf du = dx\]\[\sf \int (u-3)(u^{1/2})du\]

  7. Jhannybean
    • one year ago
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    Are you ok with solving it now?

  8. diamondboy
    • one year ago
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    hmm let me see

  9. diamondboy
    • one year ago
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    this was where I couldn't go further

  10. diamondboy
    • one year ago
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    Oh wait

  11. diamondboy
    • one year ago
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    @Jhannybean

  12. diamondboy
    • one year ago
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    |dw:1442093530081:dw|

  13. diamondboy
    • one year ago
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    @thomas5267

  14. diamondboy
    • one year ago
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    @vera_ewing

  15. diamondboy
    • one year ago
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    It's ok I finally got it

  16. Jhannybean
    • one year ago
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    Awesome! :)

  17. Jhannybean
    • one year ago
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    got the same thing.

  18. diamondboy
    • one year ago
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    |dw:1442095044771:dw|

  19. diamondboy
    • one year ago
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    This is the correct answer

  20. Jhannybean
    • one year ago
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    \[\sf \int (u-3)(u^{1/2})du\]\[\sf \int (u^{3/2} -3u^{1/2})du\]\[\sf =\frac{2}{5}u^{5/2}-3\cdot \frac{2}{3}u^{3/2}+c\]\[\sf =\frac{2}{5}u^{5/2}-2u^{3/2}+c\]\[\sf u=x+3\]

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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