anonymous
  • anonymous
What is (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2? sin^2 Θ 4cos^2 Θ 8 cos^2 Θ
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Astrophysics
  • Astrophysics
cos theta - cos theta = ?
Astrophysics
  • Astrophysics
it's like saying x - x, what does that give you?
anonymous
  • anonymous
I know that part equals out to 0, but then I'm left with (cos theta + cos theta)^2

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I can't figure that out :(
Astrophysics
  • Astrophysics
Oh but in your case, there's a right answer yay!
anonymous
  • anonymous
It becomes \[\cos ^{2}\theta + \cos ^{2}\theta\]
zepdrix
  • zepdrix
Expand? 0_o But you said x-x = 0 why not apply that thinking to the other one? x+x = 2x
anonymous
  • anonymous
That's why I'm confused, it can't just equal 2x
zepdrix
  • zepdrix
...?
zepdrix
  • zepdrix
The other one is x+x
Astrophysics
  • Astrophysics
the (cos theta+ cos theta)^2 term
Astrophysics
  • Astrophysics
cos theta + cos theta = 2cos theta, now square it
anonymous
  • anonymous
Ohhh
anonymous
  • anonymous
Well then it would be \[4\cos^2 \theta\]
anonymous
  • anonymous
Well I'm an idiot
anonymous
  • anonymous
It was simple... -_-
Astrophysics
  • Astrophysics
Lol, don't worry for some reason I was thinking costheta+ sintheta
Astrophysics
  • Astrophysics
But in any case if you took long way or just added right away, you'd get same answer
anonymous
  • anonymous
It's okay, thank you for helping though!
Astrophysics
  • Astrophysics
Yw :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.