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anonymous

  • one year ago

What is (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2? sin^2 Θ 4cos^2 Θ 8 cos^2 Θ

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  1. Astrophysics
    • one year ago
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    cos theta - cos theta = ?

  2. Astrophysics
    • one year ago
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    it's like saying x - x, what does that give you?

  3. anonymous
    • one year ago
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    I know that part equals out to 0, but then I'm left with (cos theta + cos theta)^2

  4. anonymous
    • one year ago
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    I can't figure that out :(

  5. Astrophysics
    • one year ago
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    Oh but in your case, there's a right answer yay!

  6. anonymous
    • one year ago
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    It becomes \[\cos ^{2}\theta + \cos ^{2}\theta\]

  7. zepdrix
    • one year ago
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    Expand? 0_o But you said x-x = 0 why not apply that thinking to the other one? x+x = 2x

  8. anonymous
    • one year ago
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    That's why I'm confused, it can't just equal 2x

  9. zepdrix
    • one year ago
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    ...?

  10. zepdrix
    • one year ago
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    The other one is x+x

  11. Astrophysics
    • one year ago
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    the (cos theta+ cos theta)^2 term

  12. Astrophysics
    • one year ago
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    cos theta + cos theta = 2cos theta, now square it

  13. anonymous
    • one year ago
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    Ohhh

  14. anonymous
    • one year ago
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    Well then it would be \[4\cos^2 \theta\]

  15. anonymous
    • one year ago
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    Well I'm an idiot

  16. anonymous
    • one year ago
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    It was simple... -_-

  17. Astrophysics
    • one year ago
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    Lol, don't worry for some reason I was thinking costheta+ sintheta

  18. Astrophysics
    • one year ago
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    But in any case if you took long way or just added right away, you'd get same answer

  19. anonymous
    • one year ago
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    It's okay, thank you for helping though!

  20. Astrophysics
    • one year ago
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    Yw :)

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