What is (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2? sin^2 Θ 4cos^2 Θ 8 cos^2 Θ

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What is (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2? sin^2 Θ 4cos^2 Θ 8 cos^2 Θ

Mathematics
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cos theta - cos theta = ?
it's like saying x - x, what does that give you?
I know that part equals out to 0, but then I'm left with (cos theta + cos theta)^2

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Other answers:

I can't figure that out :(
Oh but in your case, there's a right answer yay!
It becomes \[\cos ^{2}\theta + \cos ^{2}\theta\]
Expand? 0_o But you said x-x = 0 why not apply that thinking to the other one? x+x = 2x
That's why I'm confused, it can't just equal 2x
...?
The other one is x+x
the (cos theta+ cos theta)^2 term
cos theta + cos theta = 2cos theta, now square it
Ohhh
Well then it would be \[4\cos^2 \theta\]
Well I'm an idiot
It was simple... -_-
Lol, don't worry for some reason I was thinking costheta+ sintheta
But in any case if you took long way or just added right away, you'd get same answer
It's okay, thank you for helping though!
Yw :)

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