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anonymous

  • one year ago

A manufacturer of shipping boxes has a box shaped like a cube. The side length is (5a + 4b) . What is the volume of the box in terms of a and b?

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  1. calculusxy
    • one year ago
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    \[\large (5a + 4b)^3\] it is like: \[\large (5a+4b)(5a + 4b)(5a + 4b)\] i would use FOIL so let's start with \[\large (5a+4b)(5a+4b)\]

  2. calculusxy
    • one year ago
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    \[\large (5a \times 5a) + (5a \times 4b) + (4b \times 5a) + (4b \times 4b)\]

  3. calculusxy
    • one year ago
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    \[\large (5a + 4b)(25a^2 + 20ab + 20ba +16b^2)\]

  4. calculusxy
    • one year ago
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    Continue using FOIL

  5. anonymous
    • one year ago
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    whenever i watched the example video it had something to do with some kind of triangle not foil let me up load the video real quick

  6. calculusxy
    • one year ago
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    i think i understand this: |dw:1442099987991:dw|

  7. calculusxy
    • one year ago
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    the way that you get the numbers is by finding how many ways to get to the end. we have only went to the 3rd exponent because when trying to find the volume of cube, the side length is raised to the third power

  8. anonymous
    • one year ago
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    ok im following so far i understood how to do the triangle thing but what i was confused about is how to apply that to the question i had

  9. calculusxy
    • one year ago
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    we are going to use 1, 3, 3, 1 for the exponents to 5a and 4b we will go from greatest to lowest (descending) \[1(5)a^34b^0 + 3(5)a^24b^1 + 3(5)a^14b^2 + 1(5)a^04b^3\]

  10. calculusxy
    • one year ago
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    the problme is whether i should multiply the 1, 3, 3, 1 to 4

  11. anonymous
    • one year ago
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    i understand but why would u have to mutiply that in the video it just left everything like you have it in the post before this . i dont understand how your suppose to get the volume out of that but i did get how you got the (equation/ i guess you would call it that )

  12. calculusxy
    • one year ago
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    you have a number front of the variable and that is causing some problems .. n the video it was only a variable

  13. calculusxy
    • one year ago
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    *in

  14. anonymous
    • one year ago
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    :/

  15. calculusxy
    • one year ago
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    \[\large 5a^34b + 15a^212b + 15a12b^2 + 20b^3\]

  16. calculusxy
    • one year ago
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    this is what might happen if you do multiply 1,3,3,1 to 4.

  17. anonymous
    • one year ago
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    i just dont understand how you get all that down to one simply number ?

  18. calculusxy
    • one year ago
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    \[1(5)a^3(1)4b^0 + 3(5)a^2(3)4b^1 + 3(5)a^1(3)4b^2 + 1(5)a^0(1)4b^3\]

  19. calculusxy
    • one year ago
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    i basically used what the video had said.

  20. calculusxy
    • one year ago
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    @Mehek14 @mathmate

  21. anonymous
    • one year ago
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    oh i understand that i just dont understand how you get the volume out of that .

  22. calculusxy
    • one year ago
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    i am completely new to this and i tried my best to help you out

  23. anonymous
    • one year ago
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    thanks so much i really appreciate it . and i am too my teacher just sends me the video and expects me to just get it im going to look though my text book and see if i can find anything that will help me more !

  24. mathmate
    • one year ago
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    @calculusxy @iloveyoukarsonlee Recall that \(\Large (ab)^n = a^n\times b^n\) so (5a+4b)^3 =\((1)(5a)^3+(3)(5a)^2(4b)+(3)(5a)(4b)^2+(1)(4b)^3\) =\(125a^3+300a^2b+240ab^2+64b^3\)

  25. calculusxy
    • one year ago
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  26. calculusxy
    • one year ago
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    that my was my work.. if u can understand my handwriting hopefully it can help u understand my process

  27. anonymous
    • one year ago
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    yes that helps so much thank you both !!!

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