A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
A manufacturer of shipping boxes has a box shaped like a cube. The side length is
(5a + 4b)
. What is the volume of the box in terms of a and b?
anonymous
 one year ago
A manufacturer of shipping boxes has a box shaped like a cube. The side length is (5a + 4b) . What is the volume of the box in terms of a and b?

This Question is Closed

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\large (5a + 4b)^3\] it is like: \[\large (5a+4b)(5a + 4b)(5a + 4b)\] i would use FOIL so let's start with \[\large (5a+4b)(5a+4b)\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\large (5a \times 5a) + (5a \times 4b) + (4b \times 5a) + (4b \times 4b)\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\large (5a + 4b)(25a^2 + 20ab + 20ba +16b^2)\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Continue using FOIL

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whenever i watched the example video it had something to do with some kind of triangle not foil let me up load the video real quick

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i think i understand this: dw:1442099987991:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1the way that you get the numbers is by finding how many ways to get to the end. we have only went to the 3rd exponent because when trying to find the volume of cube, the side length is raised to the third power

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok im following so far i understood how to do the triangle thing but what i was confused about is how to apply that to the question i had

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1we are going to use 1, 3, 3, 1 for the exponents to 5a and 4b we will go from greatest to lowest (descending) \[1(5)a^34b^0 + 3(5)a^24b^1 + 3(5)a^14b^2 + 1(5)a^04b^3\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1the problme is whether i should multiply the 1, 3, 3, 1 to 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i understand but why would u have to mutiply that in the video it just left everything like you have it in the post before this . i dont understand how your suppose to get the volume out of that but i did get how you got the (equation/ i guess you would call it that )

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1you have a number front of the variable and that is causing some problems .. n the video it was only a variable

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[\large 5a^34b + 15a^212b + 15a12b^2 + 20b^3\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1this is what might happen if you do multiply 1,3,3,1 to 4.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just dont understand how you get all that down to one simply number ?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[1(5)a^3(1)4b^0 + 3(5)a^2(3)4b^1 + 3(5)a^1(3)4b^2 + 1(5)a^0(1)4b^3\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i basically used what the video had said.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i understand that i just dont understand how you get the volume out of that .

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i am completely new to this and i tried my best to help you out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much i really appreciate it . and i am too my teacher just sends me the video and expects me to just get it im going to look though my text book and see if i can find anything that will help me more !

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@calculusxy @iloveyoukarsonlee Recall that \(\Large (ab)^n = a^n\times b^n\) so (5a+4b)^3 =\((1)(5a)^3+(3)(5a)^2(4b)+(3)(5a)(4b)^2+(1)(4b)^3\) =\(125a^3+300a^2b+240ab^2+64b^3\)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1that my was my work.. if u can understand my handwriting hopefully it can help u understand my process

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that helps so much thank you both !!!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.