A 2.0 L vessel contains HI and H2. The following equilibrium is established:
H2 (g) + I2 (g) ⇌ 2 HI (g)
At equilibrium
[H2] = 2.0 M
[I2] = 1.5 M
[HI] = 2.5 M
The initial concentration of I2 was not mentioned so you must assume [I2]o = 0.
Calculate the initial moles of:
HI
(Tol: ± 0.1)
H2 (g)
(Tol: ± 0.1)

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@Abhisar @Photon336

You could work backwards

wait those +/- thats the change in concentration right? @Lena772

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