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anonymous

  • one year ago

Determine the slope triangle dimension s so that the horizontal components of the two forces shown are equal to magnitude and opposite in sense. Then find the resultant of the force system.

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  1. anonymous
    • one year ago
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    |dw:1442115930012:dw|

  2. anonymous
    • one year ago
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    @johnweldon1993

  3. anonymous
    • one year ago
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    before we help you, I think it would be nice for you to show us how would you approach this problem

  4. anonymous
    • one year ago
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    |dw:1442116414335:dw|

  5. anonymous
    • one year ago
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    well i got pretty much all the answer but im not sure about em. like for s, its equal 2.20

  6. anonymous
    • one year ago
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    show us

  7. anonymous
    • one year ago
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    for the resultant of 2 forces is equal 15.01 N

  8. anonymous
    • one year ago
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    show us how you got that

  9. anonymous
    • one year ago
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    gimme a sec

  10. anonymous
    • one year ago
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  11. anonymous
    • one year ago
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  12. anonymous
    • one year ago
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    |dw:1442118123396:dw|

  13. anonymous
    • one year ago
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    |dw:1442118345598:dw|

  14. anonymous
    • one year ago
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    |dw:1442118398038:dw|

  15. anonymous
    • one year ago
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    resultant forces is easy using component method, which I think you already have an idea

  16. anonymous
    • one year ago
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    the problem is the Fx is equal 0. and the Fy as u see have 2 forces on the same line

  17. anonymous
    • one year ago
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    which idk to combine em or what

  18. anonymous
    • one year ago
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    you were given a clue that both horizontal components are equal but at the same time opposite that is equal in magnitude but are opposite in directions

  19. anonymous
    • one year ago
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    horizontal component is our x component, right?

  20. anonymous
    • one year ago
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    yes

  21. anonymous
    • one year ago
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    so we got F2x and F1x which the total is equal zero

  22. anonymous
    • one year ago
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    I think it is more reasonable to show that they are opposite in direction if we preserved the angle as 140 degrees instead of 40 degrees for our second resultant force

  23. anonymous
    • one year ago
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    oh that is fine with resultant

  24. anonymous
    • one year ago
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    |dw:1442118862586:dw|

  25. anonymous
    • one year ago
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    so we just need to show it and calculate it too? cuz i tried to do like that before to solve that problem, but then i changed my mind

  26. anonymous
    • one year ago
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    lol we can calculate it using component method

  27. anonymous
    • one year ago
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    well yeah

  28. anonymous
    • one year ago
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    the problem is how can we make sure the resultant is on the y line or not. cuz if its not, then we cant solve it easily

  29. anonymous
    • one year ago
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    |dw:1442119046755:dw|

  30. anonymous
    • one year ago
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    |dw:1442119539625:dw|

  31. anonymous
    • one year ago
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    |dw:1442119666932:dw|

  32. anonymous
    • one year ago
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    lthank you so much, i will try to finish the rest :)

  33. anonymous
    • one year ago
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    |dw:1442119755305:dw|

  34. anonymous
    • one year ago
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    |dw:1442119901023:dw|

  35. anonymous
    • one year ago
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    if you preserve the angle counter-clock wise or use the quadrant as your reference, you still end up with the same answer in the end it is up to you however comfortable you are

  36. anonymous
    • one year ago
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    thank you so much :)

  37. anonymous
    • one year ago
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    let me know your final answer if you want to share

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