A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Help understanding exponent laws:
I have an equation ln(xy)=lnx+c. When I simplify a bit, I get 1y=x+e^c, but the professor writes it as 1y=cx. How is that possible?
anonymous
 one year ago
Help understanding exponent laws: I have an equation ln(xy)=lnx+c. When I simplify a bit, I get 1y=x+e^c, but the professor writes it as 1y=cx. How is that possible?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry typo.... ln(1y)**

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ln(1y)=lnx+c ..... somehow simplifies to 1y=cx. I am getting 1y=x+e^c

Empty
 one year ago
Best ResponseYou've already chosen the best response.4Well two things here, you can rewrite \[c= \ln (e^c)\] and it will combine like this: \[\ln(1y)=\ln x+\ln e^c = \ln (e^c * x)\] \[1y = e^c x\] of course since \(e^c\) is arbitrary, just making it your new constant doesn't matter.

Empty
 one year ago
Best ResponseYou've already chosen the best response.4If log rules make you uneasy, I suggest just doing it this way instead: \[\ln( 1y) = \ln x + c\] raise these as exponents: \[e^{\ln(1y)} = e^{\ln x + c}\] then you can separate out the exponents with exponent rules instead of log rules: \[e^{\ln(1y)} = e^{\ln x + c} = e^{\ln x }e^c\] And then you get the same answer

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442120586554:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you everyone. I am a little shaky on the exponent laws so that was helpful.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.