Perform the following operations to the correct number of significant figures. 257 N X 0.42 m =

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Perform the following operations to the correct number of significant figures. 257 N X 0.42 m =

Mathematics
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When multiplying 2 numbers take the least number of significant figures. how many sig figs does 257 have? how many dig figs does 0.42 have?
257 have 3 and 0.42 have 2

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so we are goona use two s.f right??
which be 107.94
Nope. 107.94 = 5 sig figs. All the numbers count, even the 0 in the middle of the 1 and 7.
but know here we have 5 s.f right
then it be 1.1X10^2
You are correct
so this be the answer
mmhmm.\(\checkmark\)
but one of my friend said that it be 110 Newton meters
how is it comes thou??
is they convert newton to meters maybe
110 = 3 sig figs which is incorrect.
no its two because the last zero doesn't count
Oh my bad. Yes, you are right, 110 has 2 sig figs, but 110. has 3
wait but how he get 110
I `think` he got 110 by rounding 107.94 to 2 decimal places... so rounding 0 to 1 without touching the decimal. Therefore it would become 110. I believe it is wrong because that is excluding all the other numbers as part of the answer, whereas \(\sf 1.1 ~\times~ 10^2\) does not disregard the other numbers, it just states that \(\sf 1.1~\times~10^2\)is a more accurate representation of the answer to 2 significant figures.
1.82 g/mL X 0.613 cm = 1.6X10^1
Is it right??
No. this is 3 s.f. x 3 s.f = 3 s.f
\[\sf 1.82~ \frac{g}{mL} ~\times ~ 0.613~cm = 1.11566 ~\frac{g}{mL}\cdot cm = 1.12~\frac{g}{mL} \cdot cm\]
wait how you get 0.613 cm
\(\color{#0cbb34}{\text{Originally Posted by}}\) @MTALHAHASSAN2 1.82 g/mL X 0.613 cm = 1.6X10^1 \(\color{#0cbb34}{\text{End of Quote}}\) I was basing it off what you wrote
oh ok the question was thou 1.82 g/mL X 8.6 mL = 1.6 X 10 ^1
sorry about that!!
okay, then your answer would be 2 s.f
\[\sf 1.82~\frac{g}{mL}~\times~8.6~mL~ =~ 15.652~g~ = ~16.~g\]

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