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MTALHAHASSAN2

  • one year ago

Perform the following operations to the correct number of significant figures. 257 N X 0.42 m =

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  1. MTALHAHASSAN2
    • one year ago
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    @Shalante

  2. Jhannybean
    • one year ago
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    When multiplying 2 numbers take the least number of significant figures. how many sig figs does 257 have? how many dig figs does 0.42 have?

  3. MTALHAHASSAN2
    • one year ago
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    257 have 3 and 0.42 have 2

  4. MTALHAHASSAN2
    • one year ago
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    so we are goona use two s.f right??

  5. MTALHAHASSAN2
    • one year ago
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    which be 107.94

  6. Jhannybean
    • one year ago
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    Nope. 107.94 = 5 sig figs. All the numbers count, even the 0 in the middle of the 1 and 7.

  7. MTALHAHASSAN2
    • one year ago
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    but know here we have 5 s.f right

  8. MTALHAHASSAN2
    • one year ago
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    then it be 1.1X10^2

  9. Jhannybean
    • one year ago
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    You are correct

  10. MTALHAHASSAN2
    • one year ago
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    so this be the answer

  11. Jhannybean
    • one year ago
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    mmhmm.\(\checkmark\)

  12. MTALHAHASSAN2
    • one year ago
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    but one of my friend said that it be 110 Newton meters

  13. MTALHAHASSAN2
    • one year ago
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    how is it comes thou??

  14. MTALHAHASSAN2
    • one year ago
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    is they convert newton to meters maybe

  15. Jhannybean
    • one year ago
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    110 = 3 sig figs which is incorrect.

  16. MTALHAHASSAN2
    • one year ago
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    no its two because the last zero doesn't count

  17. Jhannybean
    • one year ago
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    Oh my bad. Yes, you are right, 110 has 2 sig figs, but 110. has 3

  18. MTALHAHASSAN2
    • one year ago
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    wait but how he get 110

  19. MTALHAHASSAN2
    • one year ago
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    @Shalante

  20. Jhannybean
    • one year ago
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    I `think` he got 110 by rounding 107.94 to 2 decimal places... so rounding 0 to 1 without touching the decimal. Therefore it would become 110. I believe it is wrong because that is excluding all the other numbers as part of the answer, whereas \(\sf 1.1 ~\times~ 10^2\) does not disregard the other numbers, it just states that \(\sf 1.1~\times~10^2\)is a more accurate representation of the answer to 2 significant figures.

  21. MTALHAHASSAN2
    • one year ago
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    1.82 g/mL X 0.613 cm = 1.6X10^1

  22. MTALHAHASSAN2
    • one year ago
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    Is it right??

  23. Jhannybean
    • one year ago
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    No. this is 3 s.f. x 3 s.f = 3 s.f

  24. Jhannybean
    • one year ago
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    \[\sf 1.82~ \frac{g}{mL} ~\times ~ 0.613~cm = 1.11566 ~\frac{g}{mL}\cdot cm = 1.12~\frac{g}{mL} \cdot cm\]

  25. MTALHAHASSAN2
    • one year ago
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    wait how you get 0.613 cm

  26. Jhannybean
    • one year ago
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    \(\color{#0cbb34}{\text{Originally Posted by}}\) @MTALHAHASSAN2 1.82 g/mL X 0.613 cm = 1.6X10^1 \(\color{#0cbb34}{\text{End of Quote}}\) I was basing it off what you wrote

  27. MTALHAHASSAN2
    • one year ago
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    oh ok the question was thou 1.82 g/mL X 8.6 mL = 1.6 X 10 ^1

  28. MTALHAHASSAN2
    • one year ago
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    sorry about that!!

  29. Jhannybean
    • one year ago
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    okay, then your answer would be 2 s.f

  30. Jhannybean
    • one year ago
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    \[\sf 1.82~\frac{g}{mL}~\times~8.6~mL~ =~ 15.652~g~ = ~16.~g\]

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