I DON'T GET IT
How is either method wrong? - (the plus minus sign wasn't an option in their symbols bank?)
http://prntscr.com/8ft0nc
http://prntscr.com/8ft0se

- kittiwitti1

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- schrodinger

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- imqwerty

\[\sqrt{4-(2\sin \theta)^2}\]\[\sqrt{4-4\sin^2\theta} \]\[\sqrt{4(1-\sin^2\theta)}\]and 1-sin^2(theta)=cos^2theta
so we get
\[\sqrt{4\cos^2\theta}\]=\[\pm2\cos \theta\]

- kittiwitti1

I got that. The system isn't taking the answer in any form...

- imqwerty

wait :D i didn see this - \[0<\theta <90\]

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## More answers

- kittiwitti1

I tried these combinations\[\pm\sqrt{4\cos^{2}\theta}\]\[\sqrt{4\cos^{2}\theta},-\sqrt{4\cos^{2}\theta}\]yes? what does this mean?\[0\lt\theta\lt90?\]

- imqwerty

that means that the angle theta lies between 0degrees and 90 deegrees

- kittiwitti1

Yes ?
I don't know what that applies to my answer lol, don't know how to

- imqwerty

hav u tried this-
\[2\cos \theta\]

- imqwerty

tried that as the answer?

- kittiwitti1

http://prntscr.com/8ft6av?

- imqwerty

?

- kittiwitti1

I have tried the positive version already. I have only one attempt left.
However, I solved by hand and the answer I got was\[\pm2\cos\theta\]

- kittiwitti1

I mean\[\pm2\left|\cos\theta\right|\]

- imqwerty

yea

- kittiwitti1

I don't get it.
See, I got this one right without issues. http://prntscr.com/8ft75p

- kittiwitti1

Maybe they are negative?

- kittiwitti1

I can't risk the attempt though, got to make sure. :S

- imqwerty

:) if they r not accepting positive then no scope for negative

- imqwerty

maybe theres some error in their server

- kittiwitti1

"No scope"?? -Confused-
Yes maybe. One time I put space after a comma and they told me it was wrong. Someone on here said "take the space out" and I got it right after that... =_=

- imqwerty

hahaha :D these things r annoying
have u tried it like this- http://prntscr.com/8ft8mg
i mean that space between theta nd that sec or tan or whateva

- kittiwitti1

Sadly I tried it before, doesn't register as a trig function if I do that

- imqwerty

have tried any such question before ...a question in which the answer was in the form of a trigo expression?

- kittiwitti1

que?

- hartnn

i would try \( 2| \cos \theta| \) for 1st
and \(3\tan \theta \) for 2nd

- hartnn

i mean \(3 |\tan \theta |\)

- kittiwitti1

@hartnn first one does not accept
second one I cannot try, I must be sure - only one submit attempt left ^^; sorry!

- hartnn

its definitely not \(\pm\)
the answer to a \(\sqrt{...}\) is always a positive

- imqwerty

yes maybe it doesn't accept because of that bracket u put :P http://prntscr.com/8ftchw

- kittiwitti1

The coding comes with the bracket. @imqwerty I cannot remove that. I have tried that.

- kittiwitti1

@hartnn I was taught that there are two types of signs to a square root? I mean (-)(-)=+ right?

- imqwerty

u must consult ur teacher

- kittiwitti1

HAHAHAHHA my teacher is dumb she won't help me, I've tried. She sucks at technology and give us online homework LOL

- hartnn

if already not tried,
\(3 |\tan(\theta)|\) is worth trying for 2nd.
don't forget to keep the fingers crossed :P

- kittiwitti1

ehhh.
I have done that?

- imqwerty

lol

- imqwerty

is this flvs? maybe u get the solution to this issue on google :)

- hartnn

if x^2 = a
then
x = \(\pm \sqrt a\)
thats because \((\sqrt a)^2 \\ and \\ (-\sqrt a)^2 \\ \text{both equal a}\)

- hartnn

and \(\sqrt a\) is just one of them, and it can never be negative

- kittiwitti1

????????

- kittiwitti1

Ah my question key die from pressing too much LOL x_x!

- hartnn

was just trying to explain why sqrt a can never be negative

- imqwerty

so u got the 1st one wrong ....did it tell u the correct answer afterwards?

- kittiwitti1

@imqwerty No, it does not tell me the answer. :[
@hartnn I am still lost, what o-o

- kittiwitti1

...My computer is very laggy right now

- imqwerty

:)

- hartnn

go for \(3|\tan \theta |\) !

- kittiwitti1

...Fine, I blame you guys if I fail the question lol

- kittiwitti1

http://prntscr.com/8ftleb
... @hartnn it's wrong.

- kittiwitti1

I don't get iiiit! D:

- hartnn

the system should atleast take equivalent answers..
seems to be a faulty system, and an incorrect way to test students!
maybe it would have accepted
\(|3 \tan \theta |\)

- kittiwitti1

The teacher said the answer must be a|cos theta| format

- hartnn

it needs to have cos in ti ??

- kittiwitti1

no that is an example trig function

- hartnn

sec^2 x = 1/cos^2 x

- kittiwitti1

LOL

- hartnn

3 | tan \(\theta \)| is indeed in that format

- kittiwitti1

Yeah idk why they say it's wrong. This question have the right formathttp://prntscr.com/8ftnwx

- kittiwitti1

@hartnn \[\sin10=\cos{?}\]

- kittiwitti1

10 degree

- kittiwitti1

Wait never mind

- kittiwitti1

I got it

- hartnn

sin x = cos(90-x)
here x = 10
whats 90 -10 ?

- hartnn

ok

- kittiwitti1

lolol sorry

- hartnn

no problem :)

- kittiwitti1

But I don't get the formatting of those problem, confusing D:

- kittiwitti1

Also: "Use Definition II to explain why it is possible to find an angle θ that will make tan θ as large as we wish" (what?!)

- kittiwitti1

@hartnn ? ?

- hartnn

whats the Def II?
they are asking why tan 90n goes to infinity or -infinity

- kittiwitti1

Yes.
And I got wrong answer here too LOL very sorry
(8 cos 30°)2 I put 96 is wrong

- kittiwitti1

^2 sorry not x2

- hartnn

cos 30 = sqrt 3/2
8 cos 30 = 4 sqrt 3
its square
16*3 = ...

- kittiwitti1

:o
Oh um um um

- kittiwitti1

UM.... 48?!

- hartnn

yes

- kittiwitti1

lol! I got it :D

- kittiwitti1

Thank you ! :]

- hartnn

welcome ^_^

- kittiwitti1

But... what about the weird question? Do I just skip it for now? o-o

- hartnn

take 2nd opinion...
maybe ask some other expert
or you can skip it, if you're not in any hury

- kittiwitti1

Okay.

- kittiwitti1

@hartnn Sorry question: http://prntscr.com/8ftxg2 ?

- hartnn

cos 30 = sqrt 3/2
cos^2 30 = 3/4
4cos^2 30 = 3

- hartnn

6 sin 30 = 6/2 =3

- hartnn

finally, 3+3 =6

- kittiwitti1

o_o Oh.

- kittiwitti1

So I should not do it the quadratic formula way yes?

- kittiwitti1

Too complex? lol

- hartnn

you can, but that not required, because we know the values already

- kittiwitti1

ah ok. got it

- kittiwitti1

−5 sin 2x if x = 30, how much?
I don't know how to do a sin b x

- hartnn

x = 30,
so 2x = 60
sin 60 = sqrt 3/2
so -5 sqrt 3/2

- kittiwitti1

OOOOOOH okay! Thank you :)

- kittiwitti1

Umm last one, this really confusing me http://prntscr.com/8fu4ew?

- kittiwitti1

?

- kittiwitti1

@hartnn

- hartnn

tan is opposite/adjacent so it has to be the 1st one only

- kittiwitti1

Ohhh okay my brain is too tired to process right, thank you so much lol

- kittiwitti1

I gonna close this now

- hartnn

sure, welcome ^_^

- kittiwitti1

@hartnn @imqwerty the answer was right EXCEPT for the absolute value... WHAT THE HECK
Thanks hartnn I should have listened to you lol

- imqwerty

:D

- kittiwitti1

@imqwerty what?

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