kittiwitti1
  • kittiwitti1
I DON'T GET IT How is either method wrong? - (the plus minus sign wasn't an option in their symbols bank?) http://prntscr.com/8ft0nc http://prntscr.com/8ft0se
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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imqwerty
  • imqwerty
\[\sqrt{4-(2\sin \theta)^2}\]\[\sqrt{4-4\sin^2\theta} \]\[\sqrt{4(1-\sin^2\theta)}\]and 1-sin^2(theta)=cos^2theta so we get \[\sqrt{4\cos^2\theta}\]=\[\pm2\cos \theta\]
kittiwitti1
  • kittiwitti1
I got that. The system isn't taking the answer in any form...
imqwerty
  • imqwerty
wait :D i didn see this - \[0<\theta <90\]

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More answers

kittiwitti1
  • kittiwitti1
I tried these combinations\[\pm\sqrt{4\cos^{2}\theta}\]\[\sqrt{4\cos^{2}\theta},-\sqrt{4\cos^{2}\theta}\]yes? what does this mean?\[0\lt\theta\lt90?\]
imqwerty
  • imqwerty
that means that the angle theta lies between 0degrees and 90 deegrees
kittiwitti1
  • kittiwitti1
Yes ? I don't know what that applies to my answer lol, don't know how to
imqwerty
  • imqwerty
hav u tried this- \[2\cos \theta\]
imqwerty
  • imqwerty
tried that as the answer?
kittiwitti1
  • kittiwitti1
http://prntscr.com/8ft6av?
imqwerty
  • imqwerty
?
kittiwitti1
  • kittiwitti1
I have tried the positive version already. I have only one attempt left. However, I solved by hand and the answer I got was\[\pm2\cos\theta\]
kittiwitti1
  • kittiwitti1
I mean\[\pm2\left|\cos\theta\right|\]
imqwerty
  • imqwerty
yea
kittiwitti1
  • kittiwitti1
I don't get it. See, I got this one right without issues. http://prntscr.com/8ft75p
kittiwitti1
  • kittiwitti1
Maybe they are negative?
kittiwitti1
  • kittiwitti1
I can't risk the attempt though, got to make sure. :S
imqwerty
  • imqwerty
:) if they r not accepting positive then no scope for negative
imqwerty
  • imqwerty
maybe theres some error in their server
kittiwitti1
  • kittiwitti1
"No scope"?? -Confused- Yes maybe. One time I put space after a comma and they told me it was wrong. Someone on here said "take the space out" and I got it right after that... =_=
imqwerty
  • imqwerty
hahaha :D these things r annoying have u tried it like this- http://prntscr.com/8ft8mg i mean that space between theta nd that sec or tan or whateva
kittiwitti1
  • kittiwitti1
Sadly I tried it before, doesn't register as a trig function if I do that
imqwerty
  • imqwerty
have tried any such question before ...a question in which the answer was in the form of a trigo expression?
kittiwitti1
  • kittiwitti1
que?
hartnn
  • hartnn
i would try \( 2| \cos \theta| \) for 1st and \(3\tan \theta \) for 2nd
hartnn
  • hartnn
i mean \(3 |\tan \theta |\)
kittiwitti1
  • kittiwitti1
@hartnn first one does not accept second one I cannot try, I must be sure - only one submit attempt left ^^; sorry!
hartnn
  • hartnn
its definitely not \(\pm\) the answer to a \(\sqrt{...}\) is always a positive
imqwerty
  • imqwerty
yes maybe it doesn't accept because of that bracket u put :P http://prntscr.com/8ftchw
kittiwitti1
  • kittiwitti1
The coding comes with the bracket. @imqwerty I cannot remove that. I have tried that.
kittiwitti1
  • kittiwitti1
@hartnn I was taught that there are two types of signs to a square root? I mean (-)(-)=+ right?
imqwerty
  • imqwerty
u must consult ur teacher
kittiwitti1
  • kittiwitti1
HAHAHAHHA my teacher is dumb she won't help me, I've tried. She sucks at technology and give us online homework LOL
hartnn
  • hartnn
if already not tried, \(3 |\tan(\theta)|\) is worth trying for 2nd. don't forget to keep the fingers crossed :P
kittiwitti1
  • kittiwitti1
ehhh. I have done that?
imqwerty
  • imqwerty
lol
imqwerty
  • imqwerty
is this flvs? maybe u get the solution to this issue on google :)
hartnn
  • hartnn
if x^2 = a then x = \(\pm \sqrt a\) thats because \((\sqrt a)^2 \\ and \\ (-\sqrt a)^2 \\ \text{both equal a}\)
hartnn
  • hartnn
and \(\sqrt a\) is just one of them, and it can never be negative
kittiwitti1
  • kittiwitti1
????????
kittiwitti1
  • kittiwitti1
Ah my question key die from pressing too much LOL x_x!
hartnn
  • hartnn
was just trying to explain why sqrt a can never be negative
imqwerty
  • imqwerty
so u got the 1st one wrong ....did it tell u the correct answer afterwards?
kittiwitti1
  • kittiwitti1
@imqwerty No, it does not tell me the answer. :[ @hartnn I am still lost, what o-o
kittiwitti1
  • kittiwitti1
...My computer is very laggy right now
imqwerty
  • imqwerty
:)
hartnn
  • hartnn
go for \(3|\tan \theta |\) !
kittiwitti1
  • kittiwitti1
...Fine, I blame you guys if I fail the question lol
kittiwitti1
  • kittiwitti1
http://prntscr.com/8ftleb ... @hartnn it's wrong.
kittiwitti1
  • kittiwitti1
I don't get iiiit! D:
hartnn
  • hartnn
the system should atleast take equivalent answers.. seems to be a faulty system, and an incorrect way to test students! maybe it would have accepted \(|3 \tan \theta |\)
kittiwitti1
  • kittiwitti1
The teacher said the answer must be a|cos theta| format
hartnn
  • hartnn
it needs to have cos in ti ??
kittiwitti1
  • kittiwitti1
no that is an example trig function
hartnn
  • hartnn
sec^2 x = 1/cos^2 x
kittiwitti1
  • kittiwitti1
LOL
hartnn
  • hartnn
3 | tan \(\theta \)| is indeed in that format
kittiwitti1
  • kittiwitti1
Yeah idk why they say it's wrong. This question have the right formathttp://prntscr.com/8ftnwx
kittiwitti1
  • kittiwitti1
@hartnn \[\sin10=\cos{?}\]
kittiwitti1
  • kittiwitti1
10 degree
kittiwitti1
  • kittiwitti1
Wait never mind
kittiwitti1
  • kittiwitti1
I got it
hartnn
  • hartnn
sin x = cos(90-x) here x = 10 whats 90 -10 ?
hartnn
  • hartnn
ok
kittiwitti1
  • kittiwitti1
lolol sorry
hartnn
  • hartnn
no problem :)
kittiwitti1
  • kittiwitti1
But I don't get the formatting of those problem, confusing D:
kittiwitti1
  • kittiwitti1
Also: "Use Definition II to explain why it is possible to find an angle θ that will make tan θ as large as we wish" (what?!)
kittiwitti1
  • kittiwitti1
@hartnn ? ?
hartnn
  • hartnn
whats the Def II? they are asking why tan 90n goes to infinity or -infinity
kittiwitti1
  • kittiwitti1
Yes. And I got wrong answer here too LOL very sorry (8 cos 30°)2 I put 96 is wrong
kittiwitti1
  • kittiwitti1
^2 sorry not x2
hartnn
  • hartnn
cos 30 = sqrt 3/2 8 cos 30 = 4 sqrt 3 its square 16*3 = ...
kittiwitti1
  • kittiwitti1
:o Oh um um um
kittiwitti1
  • kittiwitti1
UM.... 48?!
hartnn
  • hartnn
yes
kittiwitti1
  • kittiwitti1
lol! I got it :D
kittiwitti1
  • kittiwitti1
Thank you ! :]
hartnn
  • hartnn
welcome ^_^
kittiwitti1
  • kittiwitti1
But... what about the weird question? Do I just skip it for now? o-o
hartnn
  • hartnn
take 2nd opinion... maybe ask some other expert or you can skip it, if you're not in any hury
kittiwitti1
  • kittiwitti1
Okay.
kittiwitti1
  • kittiwitti1
@hartnn Sorry question: http://prntscr.com/8ftxg2 ?
hartnn
  • hartnn
cos 30 = sqrt 3/2 cos^2 30 = 3/4 4cos^2 30 = 3
hartnn
  • hartnn
6 sin 30 = 6/2 =3
hartnn
  • hartnn
finally, 3+3 =6
kittiwitti1
  • kittiwitti1
o_o Oh.
kittiwitti1
  • kittiwitti1
So I should not do it the quadratic formula way yes?
kittiwitti1
  • kittiwitti1
Too complex? lol
hartnn
  • hartnn
you can, but that not required, because we know the values already
kittiwitti1
  • kittiwitti1
ah ok. got it
kittiwitti1
  • kittiwitti1
−5 sin 2x if x = 30, how much? I don't know how to do a sin b x
hartnn
  • hartnn
x = 30, so 2x = 60 sin 60 = sqrt 3/2 so -5 sqrt 3/2
kittiwitti1
  • kittiwitti1
OOOOOOH okay! Thank you :)
kittiwitti1
  • kittiwitti1
Umm last one, this really confusing me http://prntscr.com/8fu4ew?
kittiwitti1
  • kittiwitti1
?
kittiwitti1
  • kittiwitti1
@hartnn
hartnn
  • hartnn
tan is opposite/adjacent so it has to be the 1st one only
kittiwitti1
  • kittiwitti1
Ohhh okay my brain is too tired to process right, thank you so much lol
kittiwitti1
  • kittiwitti1
I gonna close this now
hartnn
  • hartnn
sure, welcome ^_^
kittiwitti1
  • kittiwitti1
@hartnn @imqwerty the answer was right EXCEPT for the absolute value... WHAT THE HECK Thanks hartnn I should have listened to you lol
imqwerty
  • imqwerty
:D
kittiwitti1
  • kittiwitti1
@imqwerty what?

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