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anonymous

  • one year ago

Please help me : find the limit lim (10/ln|x|) as x approaches to +infinity and then as x approaches to - infinity

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  1. hartnn
    • one year ago
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    just plug in whats \(\ln(\infty )\)

  2. anonymous
    • one year ago
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    lim

  3. anonymous
    • one year ago
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    lim 10/ln|x|

  4. hartnn
    • one year ago
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    yeah, thats the question, when you plug in the value of x. you get 10/ln |infinity| you can find that value if you know whats ln |infinity| = ...

  5. anonymous
    • one year ago
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    ... and whats the limit of ln|infinity| ?

  6. hartnn
    • one year ago
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    let me ask this way, infinity represents a very large number so logarithm of a very large number is : (A) very large number or (B) very small number ?

  7. anonymous
    • one year ago
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    a ?

  8. hartnn
    • one year ago
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    yes so ln |infinity| = infinity! and whats 10/infinity??

  9. anonymous
    • one year ago
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    the answer must be 0 ! i got the key answers

  10. anonymous
    • one year ago
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    it's the absolute value what really confuses me

  11. hartnn
    • one year ago
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    yes, 10 divided by a very large number = very small number = 0

  12. anonymous
    • one year ago
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    ok , then whats the difference between lim ln(infinity) and lim ln|infinity| ?

  13. hartnn
    • one year ago
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    |a| = a when a >= 0 and |a| = -a when a<0 example : |4| = 4, because 4 is >0 |-5| = -(-5) = 5 because -5 is <0 same goes for |infinity|

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