anonymous one year ago HELP! http://prntscr.com/8ftwgn http://prntscr.com/8ftyyr http://prntscr.com/8ftz2a http://prntscr.com/8ftz6d

1. butterflydreamer

For your first question, they've already given you the value of f(x) and g(x) so all you want to do is plug it into the equation. :) $f(x) = 9x + 4$ $g(x) = -5x + 1$ Therefore g(x) - f(x) would equal: $-5x + 1 - ( 9x + 4) = ?$

2. anonymous

=-14x-3

3. butterflydreamer

correct :)

4. anonymous

:]

5. butterflydreamer

For the next question: f (x) = 9x - 5 f (2) = 9(2) - 5 = ? Then after you find out what f(2) equals to, we want to find what g(4) equals to. So, g (x) = 6x g (4) = 6(4) = ? Then f(2) - g(4) = ?

6. anonymous

they are easy just try to simply solve it

7. anonymous

11?

8. butterflydreamer

not quiteeee. So what did you get for f(2) = ?

9. butterflydreamer

Note: f(2) = 9(2) - 5 = 18 - 5 = 13 g(4) = 6(4) = 24 f(2) - g(4) = 13 - 24 = ?

10. anonymous

oh ok so it would be -11

11. butterflydreamer

yyyep :)

12. butterflydreamer

For question 3. You need to multiply both f(x) and g(x) together. Since $f(x) = x^2 + 6x$ and $g(x) = 2x^3$ Multiply both together and we get: $f(x) \times g(x) = 2x^3 (x^2 + 6x) = ?$

13. anonymous

multiply the numbers and the powers will add

14. anonymous

would is be D?

15. butterflydreamer

yyessss ^_^

16. butterflydreamer

now for the final one. Just multiply both and see which one is correct. So what do you get when you multiply f(x) and g(x) together? $f(x) \times g(x) = 5x ( 3x - 2) = ?$

17. anonymous

18. anonymous

B***

19. anonymous

not A

20. butterflydreamer

yes A is correct but have you checked option C or D? Remember that the question says "check all correct answer(s)" :)

21. anonymous

so A, C and D are the correct answers

22. anonymous

B*

23. anonymous

-.-

24. butterflydreamer

A is correct. C is correct. But what about D?? Note: when you multiply anything by 0, the answer will be 0

25. anonymous

so D is incorrect

26. butterflydreamer

yepp :)

27. anonymous

ty

28. butterflydreamer

no problemo~