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anonymous

  • one year ago

ABCD is a trapezium. BC = 4 cm, Angle ABC = 30 degree, CD = 6 cm. Area of triangle ACB = 8 cm sq. Then the area of trapezium ABCD is?

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  1. anonymous
    • one year ago
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    |dw:1442153457354:dw|

  2. hartnn
    • one year ago
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    Area of trapezium is just 1/2* sum of its parallel sides * height right? so we need AB and height CE |dw:1442153898438:dw| CE can be found using 30 -60 -90 rule

  3. hartnn
    • one year ago
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    AB can be found since area ig given and height we just found

  4. anonymous
    • one year ago
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    Answer is coming out to be 14.8 while the actual answer is 14.

  5. hartnn
    • one year ago
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    CE = 2 16 = 2*AB AB = 8 Area = 1/2(8+ 6)* 2

  6. hartnn
    • one year ago
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    which indeed = 14

  7. hartnn
    • one year ago
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    how did you get 14.8 ? :)

  8. hartnn
    • one year ago
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    ask if any doubts...

  9. anonymous
    • one year ago
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    How come CE = 2 ?

  10. anonymous
    • one year ago
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    @hartnn ?

  11. hartnn
    • one year ago
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    |dw:1442155869078:dw| "side opposite to 30 degree is half the hypotenuse"

  12. anonymous
    • one year ago
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    Got it.

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