anonymous
  • anonymous
ABCD is a trapezium. BC = 4 cm, Angle ABC = 30 degree, CD = 6 cm. Area of triangle ACB = 8 cm sq. Then the area of trapezium ABCD is?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1442153457354:dw|
hartnn
  • hartnn
Area of trapezium is just 1/2* sum of its parallel sides * height right? so we need AB and height CE |dw:1442153898438:dw| CE can be found using 30 -60 -90 rule
hartnn
  • hartnn
AB can be found since area ig given and height we just found

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anonymous
  • anonymous
Answer is coming out to be 14.8 while the actual answer is 14.
hartnn
  • hartnn
CE = 2 16 = 2*AB AB = 8 Area = 1/2(8+ 6)* 2
hartnn
  • hartnn
which indeed = 14
hartnn
  • hartnn
how did you get 14.8 ? :)
hartnn
  • hartnn
ask if any doubts...
anonymous
  • anonymous
How come CE = 2 ?
anonymous
  • anonymous
@hartnn ?
hartnn
  • hartnn
|dw:1442155869078:dw| "side opposite to 30 degree is half the hypotenuse"
anonymous
  • anonymous
Got it.

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