anonymous one year ago Factorize (2g)^2 - 18

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1. anonymous

2(2g^2-9)

2. anonymous

using this identity a^2-b^2=(a+b)(a-b) is it possible to solve it

3. anonymous

Yes, you can $18=(3\sqrt{2})^2$ So we have $(2g)^2-(3\sqrt{2})^2$ apply the identity as required!

4. anonymous

or you can apply it after factoring out a 2 $(2g)^2-18=4g^2-18=2(2g^2-9)=2((\sqrt{2}g)^2-3^2)$