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anonymous
 one year ago
How would you get the total mass by adding 0.500 g of Ca to 50.0 mL of 1.0 M of HCL?
anonymous
 one year ago
How would you get the total mass by adding 0.500 g of Ca to 50.0 mL of 1.0 M of HCL?

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Total mass = mass of calcium + mass of HCl We know the mass of Ca so we don't have to find it. We only have to find the mass of HCl We are given with the volume and the concentration of HCl, so use n=CV equation to find the no. of moles. (C= concentration and V= volume , n= no. of moles) We know that no. of moles is equal to mass divided by the molar mass. \[n = \frac{ m }{ M }\] m= mass of HCl M= molar mass Molar mass of HCl = 1+ 35.5  36.5gmol^1 Since we know the molar mass and the no. of moles of HCl, we can find the mass of HCl

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Did u get it ? @radiskull

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lookin at it right now, wait one.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2And remember here the volume is given in milliliters, so we have to convert it to cubic decimeter to apply it to n= CV equation !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK thanks, I'll give it a try.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Anytym :) if u can give me the answer now I can check it for you !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope I couldn't figure it out, never used this equation before n = CV

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Really? At Least something like \[C = \frac{ n }{ V }\]

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Didn't u still get it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll figure it out, thankx. Appreciate it!

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Medal me if u don't mind :) And WELCOME TO OPEN STUDY !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks Rushwr very kind of you.
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