Approximate tan inverse (0.4) to 3 decimal places ( either Maclaurin or Taylor series)

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Approximate tan inverse (0.4) to 3 decimal places ( either Maclaurin or Taylor series)

Mathematics
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Hello
ok please tell me what you know about taylor and mcclaurin series please?
You're back.... I thought I had lost you
Ohh OK sorry is that I am using my phone and is kind of hard to see notifications
Oh ok that makes more sense.... Yes it is much easier on computer.
So in words then (easier) tell me what you know about taylor and mcclaurin series... I want to know where I have to start
BTW how long are you going to be here ?
I l go to my computer in a bitl
Well I am doing my own homework tonight too so on and off but I am taking a break right now so I am free
came home. Sorry i was doing homework at the park
hello... ok so quickly tell me what you know about the two series please
hold on i will send you a picture of what i did
1 Attachment
do you understand it?
the problem is that i dont get the same answer to two decimal places
Wait what answers are you getting?
I got precisely the same answers and check u used the right series.... seems right to me
Using the Mcclaurin series that is
but it is not right to 3 decimal places
what answers are you getting please?
I got .3805... for both the mcclaurin series and actually putting in tan^-1(0.4) in my calculator
ohh yeah I saw what was my problem
I had it in degrees instead of radians :/
:D yea i figured that was probably the problem... next time just post your answers and I would've known immediately Specifically from the fact that the result of arctan has to fall between -pi/4 and pi/4 meaning the degress answer is way to large to possible be the answer
This is due to the fact that tan(x) has singularities at those points.... hence arctan's range -1 to 1 corresponds to that
Ok so it looks right to me are you happy do you get what is going on... have any other questions about it?
no. Is ok thanks :)
but i am stuck with another question now

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