Approximate tan inverse (0.4) to 3 decimal places ( either Maclaurin or Taylor series)

- blackstreet23

Approximate tan inverse (0.4) to 3 decimal places ( either Maclaurin or Taylor series)

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- blackstreet23

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- blackstreet23

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## More answers

- anonymous

Hello

- anonymous

ok please tell me what you know about taylor and mcclaurin series please?

- anonymous

You're back.... I thought I had lost you

- blackstreet23

Ohh OK sorry is that I am using my phone and is kind of hard to see notifications

- anonymous

Oh ok that makes more sense.... Yes it is much easier on computer.

- anonymous

So in words then (easier) tell me what you know about taylor and mcclaurin series... I want to know where I have to start

- blackstreet23

BTW how long are you going to be here ?

- blackstreet23

I l go to my computer in a bitl

- anonymous

Well I am doing my own homework tonight too so on and off but I am taking a break right now so I am free

- blackstreet23

came home. Sorry i was doing homework at the park

- anonymous

hello... ok so quickly tell me what you know about the two series please

- blackstreet23

hold on i will send you a picture of what i did

- blackstreet23

##### 1 Attachment

- blackstreet23

do you understand it?

- blackstreet23

the problem is that i dont get the same answer to two decimal places

- anonymous

Wait what answers are you getting?

- anonymous

I got precisely the same answers and check u used the right series.... seems right to me

- anonymous

Using the Mcclaurin series that is

- blackstreet23

but it is not right to 3 decimal places

- anonymous

what answers are you getting please?

- anonymous

I got .3805... for both the mcclaurin series and actually putting in tan^-1(0.4) in my calculator

- blackstreet23

ohh yeah I saw what was my problem

- blackstreet23

I had it in degrees instead of radians :/

- anonymous

:D yea i figured that was probably the problem... next time just post your answers and I would've known immediately
Specifically from the fact that the result of arctan has to fall between -pi/4 and pi/4 meaning the degress answer is way to large to possible be the answer

- anonymous

This is due to the fact that tan(x) has singularities at those points.... hence arctan's range -1 to 1 corresponds to that

- anonymous

Ok so it looks right to me are you happy do you get what is going on... have any other questions about it?

- blackstreet23

no. Is ok thanks :)

- blackstreet23

but i am stuck with another question now

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