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Littlebird

  • one year ago

Natural silver ore contains only two different isotopes, silver-­‐107 and silver-­‐109. How many atoms of silver-­‐107 are there in a 0.156 g sample of natural silver metal?

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  1. anonymous
    • one year ago
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    \[0.156~g \times\frac{ 1~mol }{ 107~g }\times \frac{ 6.022 \times 10^{23}~atoms}{ 1~mol }\]

  2. Littlebird
    • one year ago
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    I can't believe I didn't see this! :P

  3. Littlebird
    • one year ago
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    But why doesn't isotope 109 affect the problem? Because I thought the problem implied that both isotopes are in the sample, and I have to figure out how much of the .156 g is isotope 107.

  4. anonymous
    • one year ago
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    I think isotope 109 is a detractor. The problem doesn't give any information about it, other than its existence. There's no way to include it in the calculation that I can see

  5. Littlebird
    • one year ago
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    ok :)

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