## anonymous one year ago The density of a solution of sucrose is 1.0678g/cc, and it is 17.00 percent by mass. What volume of solution in milliliters do you need to supply 41.0g of surcrose

1. Rushwr

@Photon336

2. Photon336

@Rushwr sorry cc what unit is that?

3. Rushwr

cubic centimeter

4. Rushwr

@Photon336 if the solution is 17% by mass then the other 83% should sucrose?

5. Rushwr

be ^

6. Photon336

$\frac{ 1.0678g }{ cm ^{3} }$ @Rushwr I think that 17% by mass is it's 17% sucrose by mass @peachpi what do you think?

7. anonymous

that's what I think as well

8. Rushwr

Then I guess the mass of solution is 83%

9. Photon336

I think that can find % by volume if i'm correct from that

10. anonymous

so if there's 41 g of sucrose, then the mass of the whole solution is 0.17x=41 x=241.2 g ?

11. Photon336

$\frac{ 41 }{ x } = \frac{ 17 }{ 100 }$ x = 241.2 grams @peachpi I totally agree

12. anonymous

and then from that I think use the density to find volume

13. Rushwr

yeah neh !

14. anonymous

thank you so much guys!!! @peachpi @Rushwr @Photon336

15. Rushwr

I didn't do anythn though !!!!!! Sorry about that !

16. Photon336

$\frac{ 1.067g }{ cm ^{3} } = \frac{ 241.2g }{ x}$ I guess if we had this amount of grams not sure about this

17. Photon336

no wait I think that's wrong that's the mass by volume that has to be converted to cm^3 but the conversion factor is 1:1

18. anonymous

I think you end up the same place though$\rho=\frac{ m }{ V }$ $V=\frac{ m }{ \rho }=\frac{241~g}{1.0678~g/cm^3}$

19. Photon336

interesting thanks @peachpi