anonymous
  • anonymous
The density of a solution of sucrose is 1.0678g/cc, and it is 17.00 percent by mass. What volume of solution in milliliters do you need to supply 41.0g of surcrose
Chemistry
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SOLVED
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schrodinger
  • schrodinger
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Rushwr
  • Rushwr
@Photon336
Photon336
  • Photon336
@Rushwr sorry cc what unit is that?
Rushwr
  • Rushwr
cubic centimeter

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Rushwr
  • Rushwr
@Photon336 if the solution is 17% by mass then the other 83% should sucrose?
Rushwr
  • Rushwr
be ^
Photon336
  • Photon336
\[\frac{ 1.0678g }{ cm ^{3} }\] @Rushwr I think that 17% by mass is it's 17% sucrose by mass @peachpi what do you think?
anonymous
  • anonymous
that's what I think as well
Rushwr
  • Rushwr
Then I guess the mass of solution is 83%
Photon336
  • Photon336
I think that can find % by volume if i'm correct from that
anonymous
  • anonymous
so if there's 41 g of sucrose, then the mass of the whole solution is 0.17x=41 x=241.2 g ?
Photon336
  • Photon336
\[\frac{ 41 }{ x } = \frac{ 17 }{ 100 }\] x = 241.2 grams @peachpi I totally agree
anonymous
  • anonymous
and then from that I think use the density to find volume
Rushwr
  • Rushwr
yeah neh !
anonymous
  • anonymous
thank you so much guys!!! @peachpi @Rushwr @Photon336
Rushwr
  • Rushwr
I didn't do anythn though !!!!!! Sorry about that !
Photon336
  • Photon336
\[\frac{ 1.067g }{ cm ^{3} } = \frac{ 241.2g }{ x}\] I guess if we had this amount of grams not sure about this
Photon336
  • Photon336
no wait I think that's wrong that's the mass by volume that has to be converted to cm^3 but the conversion factor is 1:1
anonymous
  • anonymous
I think you end up the same place though\[\rho=\frac{ m }{ V }\] \[V=\frac{ m }{ \rho }=\frac{241~g}{1.0678~g/cm^3}\]
Photon336
  • Photon336
interesting thanks @peachpi

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