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anonymous

  • one year ago

Find the limit of the function by using direct substitution. limit as x approaches zero of (x^2 + 5)

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  1. alekos
    • one year ago
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    just substitute x = 0 and you have the limit as x -> 0

  2. anonymous
    • one year ago
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    so 5?

  3. alekos
    • one year ago
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    yep

  4. anonymous
    • one year ago
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    can you help me with one more?

  5. alekos
    • one year ago
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    fire away

  6. anonymous
    • one year ago
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    Find the limit of the function algebraically. limit as x approaches four of quantity x squared minus sixteen divided by quantity x minus four.

  7. anonymous
    • one year ago
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    I think it's 8 but I'm not sure

  8. welshfella
    • one year ago
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    note if you plug in x = 4 you get 0/0

  9. anonymous
    • one year ago
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    so no limit?

  10. welshfella
    • one year ago
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    oh you can divide of course Silly me dividing gives x + 4

  11. anonymous
    • one year ago
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    so it is 8?

  12. anonymous
    • one year ago
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    @welshfella

  13. welshfella
    • one year ago
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    yes i would say so limits are not my strong point though just a sec

  14. anonymous
    • one year ago
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    okay

  15. welshfella
    • one year ago
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    yes 8 it is

  16. welshfella
    • one year ago
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    limit as x approaches 4 of (x^2 - 16)/ (x - 4)

  17. anonymous
    • one year ago
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    Yay! thank you

  18. welshfella
    • one year ago
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    the above link confirms it

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