Find the limit of the function by using direct substitution. limit as x approaches zero of (x^2 + 5)

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Find the limit of the function by using direct substitution. limit as x approaches zero of (x^2 + 5)

Mathematics
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just substitute x = 0 and you have the limit as x -> 0
so 5?
yep

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Other answers:

can you help me with one more?
fire away
Find the limit of the function algebraically. limit as x approaches four of quantity x squared minus sixteen divided by quantity x minus four.
I think it's 8 but I'm not sure
note if you plug in x = 4 you get 0/0
so no limit?
oh you can divide of course Silly me dividing gives x + 4
so it is 8?
yes i would say so limits are not my strong point though just a sec
okay
yes 8 it is
limit as x approaches 4 of (x^2 - 16)/ (x - 4)
http://www.wolframalpha.com/input/?i=limit+as+x+approaches+4+of+%28x%5E2+-+16%29%2F+%28x+-+4%29
Yay! thank you
the above link confirms it

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