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- anonymous

Write the equation of the line that passes through the points (3,2) and (2,3)

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- anonymous

Write the equation of the line that passes through the points (3,2) and (2,3)

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- pooja195

First we need to find the slope

- pooja195

\[\huge~\rm~\frac{ y_2-y_1 }{ x_2-x_1 }=slope\]

- anonymous

1/-1

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- pooja195

Or in other words just -1
what form do they want the equation in?

- anonymous

y=mx+b

- pooja195

oh ok so now we use the point slope equation
\[\huge~\rm~y-y_1=m(x-x_1)\]
(x1,y1)=(3,2)
m=slope which is -1
just plug in the given information and solve for y

- anonymous

what would x be?

- texaschic101

or you can use y = mx + b...either formula will work

- pooja195

x and y are just there they help to figure out the slope and the equation

- pooja195

or you can use @texaschic101 's method

- texaschic101

and you x and y points.....you can use either set (3,2) or (2,3)

- texaschic101

which formula do you want to proceed with ?

- anonymous

y=-3+b... im stuck\

- anonymous

y=mx+b (3,2)

- texaschic101

you forgot about your slope(m) of -1

- anonymous

i did -1(3)

- texaschic101

y = mx + b
slope(m) = -1
(3,2)...x = 3 and y = 2
now we sub
2 = -1(3) + b
2 = -3 + b -- add 3 to both sides
2 + 3 = b
5 = b
so your line is : y = -1x + 5 or just y = -x + 5
but if you sub in your other set of points..(2,3)
3 = -1(2) + b
3 = -2 + b
3 + 2 = b
5 = b
same thing....y = -x + 5
so either of your points will give you this answer

- texaschic101

questions ?

- texaschic101

now if they wanted the answer is point-slope form you would use :
y - y1 = m(x - x1). You could also use it for this problem but you would eventually have to change it to y = mx + b form

- anonymous

no that explains it.

- texaschic101

glad to help...but please give medal to pooja195....I kinda took over her explaining...should not have done that.

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