Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

upper and lower bounds of sin x are -1 and 1
and sin 0 = 0 so the curve goes through the origin

I know that, i'm just confused on the graphing of it. For example:
Y=20sin1/2(x-120 degree) -10

so this would be sin (x - 120°)
|dw:1442167349251:dw|

yes I figured that too, but please look the the image, I will attatch it now

ok

Problem: 3. Again the equation is: 20sin1/2(x-120deg) -10

The point that the graph passes through is 180 not 120. Or is it 120?

nevermind, I see it

Oh that makes sense now

i recall this as
\[A\sin(\psi(t-\phi))+B\]

yes, so the point that is at the origin in y = sin x is translated to \((\phi,B)\)