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basically you need to calculate P(6 red or 6 blue or 6 white)
yea pretty much in simpleest form it is what @welshfella said im not gonna go further in depth and get you confused.
Could you please bare with me and go further in steps to help me solve this. I was totally lost thats why I am here seeking help. Thank you.
to find probability of drawing 4 reds you multiply the probabilities P(red on first draw) = 6/18 = 1/3 then P(red on 2nd draw) = 5/17 do you follow that ok?
- then you find probablity of red on third and fourth draw in a similar way
now because these draws are independent to find probability of getting 4 reds you multiply them
so P( 4 reds) = 1/3 * 5/17 * A * B) where A and B are what you get for draws 3 and 4
have you any questions on the above posts?
lol well it seems @welshfella has this problem . Hope you understand ;) @amool
Thank you so much. I understand much better now.
ok sorry how did you get the 5/17.
originally there are 18 balls so after 1 red is taken out there are 5 reds left and a total of 17 balls ( as the balls are not replaced)
So for the third draw there are only 4 reds and a total of 16 balls. so P(red on 3rd draw) = 4/16 = 1/4
so for 4th draw what is P(red ball)?
so it will be 3/15 = 1/5 I think this will be the 4th draw
Thanks for baring with me now I fully know the method thank you.
When you have AND involved with probabilities think Multiply red ANd red ANd red AND red so P( 4 reds) = 1/3 * 5/17 * 1/4 * 1/5 which you can convert to a decimal as they want decimals in the answer
yeah it is .004902
yes Now the probabilities of getting 4 blues and 4 whites is exactly the same both 0.004902
Noe here we have an OR involved red OR Blue OR white In this case you ADD the probabilities (OR = ADD) so final answer is the sum of the 3 probabilities
so ts 3 * 0.004902
got it .014706