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anonymous
 one year ago
An urn contains six red balls, six white balls, and six blue balls, and sample of four balls is drawn at random without replacement.
Compute the probability that all of the balls in the sample are the same color. (Round your answer to four decimal places.)
anonymous
 one year ago
An urn contains six red balls, six white balls, and six blue balls, and sample of four balls is drawn at random without replacement. Compute the probability that all of the balls in the sample are the same color. (Round your answer to four decimal places.)

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2basically you need to calculate P(6 red or 6 blue or 6 white)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea pretty much in simpleest form it is what @welshfella said im not gonna go further in depth and get you confused.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you please bare with me and go further in steps to help me solve this. I was totally lost thats why I am here seeking help. Thank you.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2to find probability of drawing 4 reds you multiply the probabilities P(red on first draw) = 6/18 = 1/3 then P(red on 2nd draw) = 5/17 do you follow that ok?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 then you find probablity of red on third and fourth draw in a similar way

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2now because these draws are independent to find probability of getting 4 reds you multiply them

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so P( 4 reds) = 1/3 * 5/17 * A * B) where A and B are what you get for draws 3 and 4

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2have you any questions on the above posts?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol well it seems @welshfella has this problem . Hope you understand ;) @amool

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much. I understand much better now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok sorry how did you get the 5/17.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2originally there are 18 balls so after 1 red is taken out there are 5 reds left and a total of 17 balls ( as the balls are not replaced)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2So for the third draw there are only 4 reds and a total of 16 balls. so P(red on 3rd draw) = 4/16 = 1/4

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so for 4th draw what is P(red ball)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it will be 3/15 = 1/5 I think this will be the 4th draw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for baring with me now I fully know the method thank you.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2When you have AND involved with probabilities think Multiply red ANd red ANd red AND red so P( 4 reds) = 1/3 * 5/17 * 1/4 * 1/5 which you can convert to a decimal as they want decimals in the answer

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes Now the probabilities of getting 4 blues and 4 whites is exactly the same both 0.004902

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Noe here we have an OR involved red OR Blue OR white In this case you ADD the probabilities (OR = ADD) so final answer is the sum of the 3 probabilities
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