Photon336 one year ago An acid with a Ka of 2x10^-6 is used to make a buffer. what is the approximate pH of the solution if the buffer has equal concentrations of both the acid and its conjugate base?

1. Photon336

Between 4-5 2-3 3-4 5-6

2. Photon336

@Rushwr @Woodward

3. Photon336

$Ka = \frac{ [H ^{+}][A ^{-}] }{ [HA] }$

4. Photon336

pH = pKa + log [A-/HA] I guess if the concentration of acid HA equals the conjugate base A- Log[1] = 0 So the pH would be equal to the pKa and I guess this would be where the greatest buffering capacity would be. PH = pKa

5. anonymous

Yeah, definitely that's what I was thinking that looks right to me.