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anonymous
 one year ago
The position of an object at time t is given by s(t) = 4  2t. Find the instantaneous velocity at t = 6 by finding the derivative.
anonymous
 one year ago
The position of an object at time t is given by s(t) = 4  2t. Find the instantaneous velocity at t = 6 by finding the derivative.

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.0well, what is our derivative?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea how to start it that's the problem @amistre64

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0your course materials should have a basic guideline, what have you covered?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0how do you define a deriative?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know but none of them look like this. They never went over a problem like this with velocity

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0lets start with how you define the derivative, what does your material say

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0does slope play into it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0then give me your best understanding of the concept of a derivative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is what we are suppose to use but it's confusing http://www.sosmath.com/calculus/diff/der00/der00.html

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0i agree that the technical part of it may be confusing, but the concept is pretty simple ... most concepts are. the derivative can tell us the slope of a tangent line to a curve at any given point. and it is said that a line is tangent to itself ... does this mean anything to you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If i followed the formula somewhat it would be 2 but that makes no sense to me

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0mathically, there is a long process that can be worked out with the limit of the difference quotient. \[\lim_{h\to 0}\frac{f(x+h)f(x)}{(x+h)x}\] let f(x) be a line ... mx+b \[\lim_{h\to 0}\frac{m(x+h)+b(mx+b)}{(x+h)x}\] \[\lim_{h\to 0}\frac{mx+mh+bmxb}{h}\] \[\lim_{h\to 0}\frac{mh+bb}{h}\] \[\lim_{h\to 0}\frac{mh}{h}\] \[\lim_{h\to 0}m\frac{h}{h}\] \[\lim_{h\to 0}m\] the derivative of a line, is just its slope, m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x)=−4−2x f(x+h)=−4−2(x+h) f′(x)=limh→0f(x+h)−f(x)h→limh→0−4−2(x+h)−(−4−2x)h

amistre64
 one year ago
Best ResponseYou've already chosen the best response.02 is the derivative of your line equation. so yes. for any value of t, the derivative is a constant 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh geez. I overcomplicated it

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0s(t) = 42t v(t) = 2
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