Math question

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you have a possible answer for this one? If so, remember to also show your work you did to arrive at your result.
I'm pretty sure it's D. I graphed it and it passes through (-2,4)
yes D.. but here how i work it...\[-7y=-14x+1\]\[y=\frac{ -14x }{ -7 }-\frac{ 1 }{ 7 }\]\[y=2x-\frac{ 1 }{ 7 }\]so ur slope=2 and since perpendicular \[m _{1}*m _{2}=-1\]where \[m _{1}=2\]now substituting that we get \[2m _{2}=-1\]\[m _{2}=\frac{ -1 }{ 2 }\]now using given point (-2,4 )|dw:1442170139078:dw|

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Oh ok thanks so much!

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