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anonymous

  • one year ago

Which of the following is false for f(x) = (10x^3 - 10x^2 - 10x) / (2x^5 - 2x) ? (a) The y-axis is not an asymptote of f(x). (b) The x-axis is an asymptote of f(x). (c) x = –1 is not an asymptote of f(x). (d) x = 1 is an asymptote of f(x). So, I took a quiz that had this question and I, of course, got it wrong. The first time that I took the quiz, it had a similar question to the one above and the second time I had taken it, it had this exact one. For the question above, I chose answer choice (a), because the first time I had chosen (c). Can someone PLEASE help me?

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  1. campbell_st
    • one year ago
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    well if you factor the numerator and denominator you get \[f(x) = \frac{10x(x^2 - x -1)}{2x(x^4 - 1)} = \frac{5(x^2 - x - 1)}{x^4 - 1}\] so the function has vertical asymptotes at x^4 = 1 or x = -1 and x = 1

  2. campbell_st
    • one year ago
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    there is a point of discontinuity at x = 0 since the degree of the denominator is greater than the degree of the numerator y = 0 is an asymptote so the x-axis is an asymptote

  3. campbell_st
    • one year ago
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    so the point of discontinity is the y- intercept (0, 5) so I think the curve is |dw:1442175602395:dw|

  4. campbell_st
    • one year ago
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    the point of diswingspaninuity occurs because you factor 10x in the numerator and 2x in the denominator... which simplifies to 2

  5. anonymous
    • one year ago
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    Would the answer then be (c) because x = -1 is an asymptote of f(x)? Because if it is, I don't know why it told me that I got the answer wrong the first time.

  6. campbell_st
    • one year ago
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    well the question asks, which is false...

  7. campbell_st
    • one year ago
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    so I think its A

  8. campbell_st
    • one year ago
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    well its A or B I just checked the graph |dw:1442176003475:dw|

  9. campbell_st
    • one year ago
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    you cam graph the curve using https://www.desmos.com/calculator and make your own decisions.

  10. anonymous
    • one year ago
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    Well, I chose (a) and it said that that was the wrong answer, too. So I'm kind of confused.

  11. anonymous
    • one year ago
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    Either way, thanks for the help :) @campbell_st

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