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shelby1290

  • one year ago

A golf ball is hit and its height is given by the equation h=29.4t - 4.9t^2, where t is the time elapsed, in seconds, and h is the height in metres.

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  1. shelby1290
    • one year ago
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    a) Write an equation in function notation to represent the height of the ball as a function of time b) State the degree of this function and whether the function is linear or quadratic. c) Use difference tables to confirm your answer in part (b) d) Graph the function where {tER | t > 0} e) At what time(s) is the ball at its greatest height? Express the height of the ball at this time in function notation f) At what time (s) is the ball on the ground? Express the height of the ball att this time in function notation

  2. diamondboy
    • one year ago
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    Hi

  3. shelby1290
    • one year ago
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    Hi, can you please help me with this question?

  4. shelby1290
    • one year ago
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    @diamondboy ^

  5. diamondboy
    • one year ago
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    I think some could be done

  6. diamondboy
    • one year ago
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    how far have u gone?

  7. diamondboy
    • one year ago
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    Lets start from the very last question (f)

  8. diamondboy
    • one year ago
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    What is the height when it touches the ground

  9. shelby1290
    • one year ago
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    I haven't started it because i don't understand what to do... Why can't we start from part a) ?

  10. shelby1290
    • one year ago
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    And go in order?

  11. diamondboy
    • one year ago
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    ok...Lets start with a)

  12. diamondboy
    • one year ago
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    |dw:1442180642592:dw| Do you understand how that happened

  13. shelby1290
    • one year ago
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    yes because you put it in function notation

  14. diamondboy
    • one year ago
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    yes....so lets go to the next one

  15. diamondboy
    • one year ago
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    so it's in the second degree therefore it is what?

  16. shelby1290
    • one year ago
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    @diamondboy quadratic

  17. diamondboy
    • one year ago
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    good

  18. diamondboy
    • one year ago
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    wat do u think abt question d and f

  19. shelby1290
    • one year ago
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    @diamondboy How do you make a graph for {tER | t > 0} in part d?

  20. diamondboy
    • one year ago
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    If I could figure out what the tER meant?

  21. shelby1290
    • one year ago
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    {TER | T > 0} TER = any real number

  22. diamondboy
    • one year ago
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    Ok

  23. diamondboy
    • one year ago
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    So thats good that means we would have to pick any real number greater than 0, make a table and graph our data

  24. shelby1290
    • one year ago
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    yes

  25. shelby1290
    • one year ago
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    |dw:1442183048636:dw|

  26. shelby1290
    • one year ago
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    @diamondboy like that? ^

  27. diamondboy
    • one year ago
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    yes

  28. diamondboy
    • one year ago
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    is that good?

  29. shelby1290
    • one year ago
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    |dw:1442183871319:dw|

  30. shelby1290
    • one year ago
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    @diamondboy all of the 2nd differences are constant. they add up to -9.8. That makes it quadratic

  31. shelby1290
    • one year ago
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    How do i graph it ?

  32. diamondboy
    • one year ago
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    You simply|dw:1442184273390:dw|

  33. shelby1290
    • one year ago
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    |dw:1442184408996:dw|

  34. shelby1290
    • one year ago
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    my line isn't perfect but something like that, right?

  35. diamondboy
    • one year ago
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    |dw:1442184387663:dw|

  36. diamondboy
    • one year ago
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    something like that but you should have a curve

  37. diamondboy
    • one year ago
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    is this a calc 1 class

  38. shelby1290
    • one year ago
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    so its at its highest point at 3 seconds or f(3)= 29.4 (3) - 4.9 (3)^2 in function notation ?

  39. shelby1290
    • one year ago
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    This is 11th Grade Functions (i'm from Canada)

  40. diamondboy
    • one year ago
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    ok

  41. diamondboy
    • one year ago
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    hmmm...the reason I asked is I wanted to use the first derivative to find the maximum height

  42. shelby1290
    • one year ago
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    and the ball is at the ground at 0 f(0) = 29.4 (0) -4.9(0)^2

  43. shelby1290
    • one year ago
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    Oh i don't remember learning about first derivatives

  44. diamondboy
    • one year ago
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    but from the graph the highest point is at 3 seconds...and remember u are not using "f" you are using h

  45. diamondboy
    • one year ago
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    well yes you could do the last one like that or equate d equation to 0

  46. shelby1290
    • one year ago
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    alright so... h(3)= 29.4 (3) - 4.9 (3)^2

  47. shelby1290
    • one year ago
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    how do you equate the equation to 0?

  48. diamondboy
    • one year ago
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    |dw:1442184935394:dw|

  49. diamondboy
    • one year ago
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    you see that?

  50. shelby1290
    • one year ago
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    oh okay, you evaluated it....

  51. shelby1290
    • one year ago
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    Alright, well thank you so much for helping me!

  52. diamondboy
    • one year ago
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    Thank God

  53. diamondboy
    • one year ago
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    Moreover you also did a great job

  54. shelby1290
    • one year ago
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    thanks

  55. diamondboy
    • one year ago
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    Thank God... :)

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