## anonymous one year ago Three consecutive integers have a sum of 87 .. What are the integers ?!

The options are endless...Any answer choices?

2. anonymous

No...

3. freckles

Let n-1 be an integer. The next integer is n. The next integer after that would be n+1. so just solve the equation: (n-1)+n+(n+1)=87

What he said xD Any questions?

5. anonymous

I get 2n^3=86 then what?

6. freckles

oh mine how did you get that

Did you tell her to divide 86 into 3 first THEN do this?

8. freckles

how many n's do you see here n, n , n?

9. anonymous

3..

10. freckles

n+n+n=3n

11. freckles

-1+1=0

12. freckles

$(n-1)+n+(n+1)=87 \\(n+n+n)+(-1+1)=87 \\ 3n+0=87 \\ 3n=87$

13. freckles

n+n+n=3n just like 4+4+4=3(4) or 12

14. anonymous

15. freckles

3n=87 gives n=29 n-1=? n+1=?

16. anonymous

28,29,30

17. freckles

put n to be 29 these questions I just asked you are equivalent to: n-1=29-1=28 n+1=29+1=30 yes 28+29+30=87

18. freckles

yep we had to find the number before and after 29 since we used (n-1) and n and (n+1) to be are integer where n we found to be 29

19. anonymous

Thank you .. Can u stick around and help me with some other problems?

20. freckles

I can probably help with one more

21. anonymous

Write 7/3 as a mixed number

22. anonymous

How do I start?

23. freckles

how many times does 3 go into 7? or how many 3's are in 7?

24. anonymous

2.3

25. freckles

7=3+3+1 how many 3's do you see?

26. anonymous

2

27. freckles

right so far we have: $\frac{7}{3}=2 \frac{?}{3}$

28. freckles

the question mark is the remainder

29. anonymous

1

30. freckles

7=3+3+1 right that 1 right there was left over

31. freckles

so the question mark is 1

32. anonymous

Thank you!

33. freckles

np