anonymous
  • anonymous
Three consecutive odd integers have a sum of 45. Find the integers
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@freckles
vera_ewing
  • vera_ewing
So you know that the integers have to be odd, right?
anonymous
  • anonymous
Ya ..

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vera_ewing
  • vera_ewing
And they have to be consecutive. (1, 2, 3)
vera_ewing
  • vera_ewing
So just try it! Start with 13.
vera_ewing
  • vera_ewing
What is 13+15+17?
anonymous
  • anonymous
Lol 😐😐😐😑😑 I'm dumb
vera_ewing
  • vera_ewing
It's simple addition. Use a calculator if you absolutely have to.
anonymous
  • anonymous
Can you help me with some more in a bit if I message you?
vera_ewing
  • vera_ewing
I'll try.
anonymous
  • anonymous
Thanks babe!
Jhannybean
  • Jhannybean
consecutive odd integers: have a difference of 2 between each of the numbers, and theyre odd, aka 1,3,5... etc \[2n + (2n+1) +(2n+3)=45\]
freckles
  • freckles
I would solve the equation n+(n+2)+(n+4)=45 but I think @Jhannybean meant to say (2n-1)+(2n+1)+(2n+3)=45 which is also a great route to go :)
Jhannybean
  • Jhannybean
Oh that's right, thanks @freckles :D

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