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anonymous

  • one year ago

Three consecutive odd integers have a sum of 45. Find the integers

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  1. anonymous
    • one year ago
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    @freckles

  2. vera_ewing
    • one year ago
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    So you know that the integers have to be odd, right?

  3. anonymous
    • one year ago
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    Ya ..

  4. vera_ewing
    • one year ago
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    And they have to be consecutive. (1, 2, 3)

  5. vera_ewing
    • one year ago
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    So just try it! Start with 13.

  6. vera_ewing
    • one year ago
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    What is 13+15+17?

  7. anonymous
    • one year ago
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    Lol πŸ˜πŸ˜πŸ˜πŸ˜‘πŸ˜‘ I'm dumb

  8. vera_ewing
    • one year ago
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    It's simple addition. Use a calculator if you absolutely have to.

  9. anonymous
    • one year ago
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    Can you help me with some more in a bit if I message you?

  10. vera_ewing
    • one year ago
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    I'll try.

  11. anonymous
    • one year ago
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    Thanks babe!

  12. Jhannybean
    • one year ago
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    consecutive odd integers: have a difference of 2 between each of the numbers, and theyre odd, aka 1,3,5... etc \[2n + (2n+1) +(2n+3)=45\]

  13. freckles
    • one year ago
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    I would solve the equation n+(n+2)+(n+4)=45 but I think @Jhannybean meant to say (2n-1)+(2n+1)+(2n+3)=45 which is also a great route to go :)

  14. Jhannybean
    • one year ago
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    Oh that's right, thanks @freckles :D

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