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anonymous
 one year ago
Three consecutive odd integers have a sum of 45. Find the integers
anonymous
 one year ago
Three consecutive odd integers have a sum of 45. Find the integers

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vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1So you know that the integers have to be odd, right?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1And they have to be consecutive. (1, 2, 3)

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1So just try it! Start with 13.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol πππππ I'm dumb

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1It's simple addition. Use a calculator if you absolutely have to.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with some more in a bit if I message you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0consecutive odd integers: have a difference of 2 between each of the numbers, and theyre odd, aka 1,3,5... etc \[2n + (2n+1) +(2n+3)=45\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.3I would solve the equation n+(n+2)+(n+4)=45 but I think @Jhannybean meant to say (2n1)+(2n+1)+(2n+3)=45 which is also a great route to go :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh that's right, thanks @freckles :D
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