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anonymous
 one year ago
how do i solve x = (2y3)/(y+1) for y?
anonymous
 one year ago
how do i solve x = (2y3)/(y+1) for y?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st @mathmate @mathway @aaronq @Teddyiswatshecallsme

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@rishavraj @Nnesha @Owlcoffee @LazyBoy @Shalante

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i multiplied y+1 on both sides is that right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure how to isolate y from there tho

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0if you multiply by the denominator you get \[x(y + 1) = 2y  3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got that far @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0then distribute \[xy + x = 2y  3\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0subtract 2y from both sides \[xy  2y + x = 3\] factor and you get \[y(x  2) + x = 3 \]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0next subtract x \[y(x 2) = x 3\] lastly divide both sides by (x  2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so y = (x3) over (x2)? @campbell_st

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1Whenever we are told to "solve for a variable" we mean doing the necessary operations to isolate it on any side of the "=" sign. So, on the equation: \[x = \frac{(2y3) }{ (y+1) }\] We are asked to solve for "y" so we will do what is necessary to leave "y" on any side of the equality. It is also important to note that this equation is solved for "x", since "x" is isolated on the left side of the equation. "x" itself represents a fraction with denominator "1" so therefore, we can treat this equation as a proportion: \[\frac{ x }{ 1 }= \frac{(2y3) }{ (y+1) }\] So we will cross multiply: \[x(y+1)=2y3\] Applying distributive property: \[xy+x=2y3\] This is the key step, we will transfer all the "y"s to the left side of the equation and obtain: \[xy2y=x3\] Now, we will take common factor "y", since it is repeated in both terms of the left side: \[y(x2)=x3\] If we divide both sides by (\(x+2\)) we will obtain: \[y=\frac{ x3 }{ x2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you! i get it now @Owlcoffee

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@Owlcoffee Whenever we divide an expression by another ( x2, in this case), it is necessary to specify the condition that x2\(\ne\)0 to be mathematically correct. This is because the results are invalid if we divide by zero.

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.1That would be true if the relationship between the variables were functional, since we don't know that, we cannot specify any conditions.
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