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anonymous
 one year ago
integrate
anonymous
 one year ago
integrate

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.3what have you considered?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442184148009:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3what is the derivative of: e^(kx) with respect to x? for some constant k

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3ok, so this derivative looks similar to what we have, it differs by a sign right? lets alter its appearance some; multiply it by (1/1)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3\[\int\frac{1}{1}\frac14e^{x/4}dx\] \[\int\frac{1}{1}\frac{1}4e^{x/4}dx\] \[\frac{1} {1}\int\frac{1}4e^{x/4}dx\] or simply \[\int\frac{1}4e^{x/4}dx\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3we know an antiderivative of the integral so, we should certainly be able to use it for a solution

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3usubbing is a valid process, but i find that training yourself to see the possibilities of where it comes from is more conducive with timed tests :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3dw:1442184708371:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.3dw:1442184778575:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much @amistre64

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0put x/4=t x=4t dx=4 dt \[I=\frac{ 1 }{ 4 }\int\limits e^t(4~dt)=e^t+c=e ^{\frac{ x }{ 4 }}+c\]
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