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anonymous
 one year ago
Find the second derivative of 3x^25y^2=1.
anonymous
 one year ago
Find the second derivative of 3x^25y^2=1.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have the first derivative. \[\frac{ dy }{ dx } = \frac{ 6x }{ 10y }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2(3*2)x^21  2*5y^21(dy/dx)=0 \[6x 10y \frac{ dy }{ dx }=0\]\[\frac{ 6x }{ 10y }=\frac{ dy }{ dx }\]\[\frac{ 3x }{ 5y }=\frac{ dy }{ dx }\]\[\frac{ (5y)(3)(3x)(5\frac{ dy }{ dx }) }{ (5y)^{2} }\]\[\frac{ 15y15x(\frac{ 3x }{ 5y}) }{ (5y)^2 }\]....can u simplify frm here...?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2i used the quotient rule...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can get that far with the quotient rule and understand why. Simplification is where I start to get careless I think.....

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 15y3x(\frac{ 3x }{ y }) }{ (5y)^2 }\]\[\frac{ 15y\frac{ 9x^2 }{ y } }{ (5y)^2 }\]\[\frac{ \frac{ (15y^29x^2) }{ y } }{ (5y)^2}\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 15y^29x^2 }{ y }*\frac{ 1 }{ (5y)^2 }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 15y^29x^2 }{ (y)(5y)^2 }\]\[\frac{ 15y^29x^2 }{ (y) (25y^2)}\]\[\frac{ 15y^2 }{ 25y^3 }\frac{ 9x^2 }{ 25y^3 }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 3 }{ 5y}\frac{ 9x^2 }{ 25y^3 }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2ok thats the simplest i can go with this
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