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anonymous
 one year ago
A man takes a photo of a bridge on holiday. The arch of
the bridge in her photograph can be modelled by the equation
y = −0.11x
2 + 1.26x + 1.20,
where x is the horizontal distance of the inner edge of the bridge from
the centre line of the photo, and y is the vertical distance from the
bottom of the photo (both measured in cm).
(i) Find the yintercept of the parabola y = −0.11x^2 + 1.26x + 1.20.
(ii) (1) Find the coordinates of the point where the line x = 9 meets
the parabola.
anonymous
 one year ago
A man takes a photo of a bridge on holiday. The arch of the bridge in her photograph can be modelled by the equation y = −0.11x 2 + 1.26x + 1.20, where x is the horizontal distance of the inner edge of the bridge from the centre line of the photo, and y is the vertical distance from the bottom of the photo (both measured in cm). (i) Find the yintercept of the parabola y = −0.11x^2 + 1.26x + 1.20. (ii) (1) Find the coordinates of the point where the line x = 9 meets the parabola.

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yintercept is a point when line line intersect yaxis when x =0 so to find yintercept substitute x for 0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0y= .11x isn't a parabola

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0oh nvm y = −0.11x^2 + 1.26x + 1.20. this is your equation so replace all x's with 0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0question ???? understood? or not ? ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what i dont get is the second part
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