Given the lim(3x-7)=2 as x-->3. Using the epsilon-delta definition for the given epsilon=.01 find the corresponding delta > 0 such that |(3x-7) - 2| < .01 whenever |x-3| < delta

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\[\large\rm |3x-9|\lt0.01\]Do you see it? :) It's so close!!

X < 3.003?

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