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Hya

hello

I'm not good at this :P

I'll give you a medal :D

I need help not medal lol

:P

HI!!

i cannot think of a snappy way to do this, this is going to take like forever

first you have to think of all the possible outcomes when you pick 4 balls

could you lead me through the problem step by step please.

if i had like two hours i could
lets at least begin

sure thing thanks

ok that is not quite right, the probabilty is \[\frac{\binom{6}{4}}{\binom{15}{4}}\]

that is \(\frac{1}{91}\)
http://www.wolframalpha.com/input/?i=%286+choose+4%29%2F%2815+choose+4%29

the problem gets tough here on out i don't know what to do from here

P(1 red)=6C1×9C3/15C4
P(2 red)=6C2×9C2/15C4
P(3 red)=6C3×9C1/15C4
P(4 red)=6C4/15C4
correct way

i didn't understand anything from here on out \

E(X) = a loss of $2.41.

Expected net winnings = -$2.41.

give me medal?