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anonymous
 one year ago
Piecewise function question
anonymous
 one year ago
Piecewise function question

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = x+4 = \left\{\begin{array}{rcc} x + 4 & \text{if} & x \geq 4 \\  x  4& \text{if} & x < 4 \end{array} \right. \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i have a graph that i really need help on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could you please hhelp me out

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you need to graph something?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no ive got a graph and have some questions about it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok i can try to help, post the picture

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i can post a picture of the worksheet so it'll be easier to see the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay pleasegive me a sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is the graph and the first question is f(1)=

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i got 3 as the answer

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh i thought you had to find the function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and the next one is f(11)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but on the graph its only till 10

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then we better find the function for \(x\leq 5\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you got the slope right, it is \(\frac{1}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that is the slope

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1goes through the point \((5,3)\) so it is \[y+5=\frac{1}{2}(x3)\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you can plug 11 in to that if you like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh alright that makes sense

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1or else write it as \[y=\frac{1}{2}(x3)+5\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1whoah did i screw that up!!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1slope is \(\frac{1}{2}\) point is \((5,3)\) equation is \[y3=\frac{1}{2}(x+5)\] doe

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so its y= 1/2(x+5)+3?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1or \[y=\frac{x}{2}+\frac{11}{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright let me solve one sec

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1did you get zero yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so the next one says find x when f(x)=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not supposed to use decimals

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you found \(f(11)=0\) right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so that makes "find x when f(x)=0" rather obvious !!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol idk why i put 5/2

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1plug in \(11\) get out zero !!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright then lol on to the next one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have to find the x intercepts

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok we got one right? one is \(11\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i got (5/2,0) and (11,0)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1there is another as well, because it is coming back up at the end and that little arrow indicates it continues up

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lets just find the damn function and be done with it k?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it actually says to write in point slope form and restricted domain in inequality form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so basically its asking me to write a fuction for each piece

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1right so far we are at \[f(x) = \left\{\begin{array}{rcc} y3=\frac{1}{2}x+5 & \text{if} & x <5 \\ 3& \text{if} & 5\leq x\leq 1 \end{array} \right.\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1what is the slope of the next piece? it is a little hard for me to see it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you said in the first function theres a 3 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0under where you write the 5 in the first equation

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is a constant (horizontal line) between 5 and 1 right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ooh damn i made a typo there forgot the parentheses

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = \left\{\begin{array}{rcc} y3=\frac{1}{2}(x+5) & \text{if} & x <5 \\ 3& \text{if} & 5\leq x\leq 1 \end{array} \right.\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im a little confused

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok lets go slow and make sure you get it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0under the first equation you put a 3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yeah we are not done you see how you have 4 long lines in your answer space?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1because this piecewise function has four distinct parts

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay yes i understand now thank you :)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1on the interval from \(5\) to \(1\) the function is a constant, it is \(f(x)=3\) a horizontal line

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so the second line down on the left you should have \(3,5\leq x\leq 1\) because on that interval it is 3

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1the next line has slope \(2\) and goes through \((1,3)\) so its equation is \[y=y3=2(x1)\] in point slope form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the slope not be a 0?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yes, the slope is zero, the equation is \(y=3\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = \left\{\begin{array}{rcc} \frac{1}{2}(x+5)+3 & \text{if} & x <5 \\ 3& \text{if} & 5\leq x\leq 1\\ 2(x1)+3 &\text{if}&1<x<6 \end{array} \right.\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1last one also has slope \(\frac{1}{2}\) right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and goes through the point \((6,7\)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x) = \left\{\begin{array}{rcc} \frac{1}{2}(x+5)+3 & \text{if} & x <5 \\ 3& \text{if} & 5\leq x\leq 1\\ 2(x1)+3 &\text{if}&1<x<6\\ \frac{1}{2}(x6)7&\text{if}&x\geq6 \end{array} \right.\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i got it i just have a couple of small questions that i wanted to confirm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are the x intercepts (5/2,0) and (11,0)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yes, but there is one more

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1set \[\frac{1}{2}(x7)7=0\] for to find the last one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{2}(x6)7=0\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1that is the part on the right think you get \(20\) if i did it right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was solving it one sec ill confirm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and the range is (infinity, infintiy)?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yeah that is what the arrows indicate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and the positives are (11, 5/2)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thast the last one haha

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i don't know what that means

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1oh you mean the interval over which it is positive ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the positives as in the parts in the upper part of the graph

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[(11,\frac{5}{2})\] is one interval but there is another

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1since it is zero at 20, and it keeps going up, the other one is \((20,\infty)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alrighty thank you so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im just putting the functions in slope intercept form now and the doamins in interval notation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill be done in a sec if you have time to check those

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=3 y=2x+5 y=1/2x10

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1slope intercept for the first one yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i am doing slope intercept for all of them

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok let me scroll way up and see i know the first two are right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay annddd the last one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yeah that also looks good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and the interval notation is (infinity, 5)? for the first one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0[5,1] (1,6) (infinity, 6]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1second interval should be \([5,1]\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and also do not put infinity on the left on the last interval!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think thats what i said for the second one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1should be on the right, go from least to greatest i.e. \((6,\infty)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the first interbal correct?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\((\infty,5)\) yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and for the last one do i use a bracket before 6 since its greater than or equal to

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1since it meets up there it is your choice

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1btw usually these piecewise functions are written with inequalities not intervals but if you are supposed to use intervals that is fine too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah it asked us to write it nboth wwyas

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you think i should use a bracket?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1kk makes no difference

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yw ms kumar lol \[\huge \color\magenta\heartsuit\]
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