anonymous
  • anonymous
I just need someone to check my answers in using matrices to determine the coordinates of matrices.
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
http://prntscr.com/8g2uxw
anonymous
  • anonymous
For both answers I got C. http://prntscr.com/8g2v9u
LynFran
  • LynFran
for this 1...its A http://prntscr.com/8g2v9u

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anonymous
  • anonymous
Ah, that was my first assumption, but I second guessed myself.
LynFran
  • LynFran
and for the other its A too
LynFran
  • LynFran
we use the x axis matrix \[\left[\begin{matrix}1 & 0 \\ 0 & -1\end{matrix}\right]\]times it by each vertex to find solution of its it image
LynFran
  • LynFran
the 270 degree matrix \[\left[\begin{matrix}0 & 1 \\ -1 & 0\end{matrix}\right]\]we do the same here too
anonymous
  • anonymous
Thanks! I really appreciate your explanations because matrices have been giving me such a hard time.
LynFran
  • LynFran
example with vertices V(8,4) and we want its image that was revolve 270 degree we multiply that by its matrix \[\left[\begin{matrix}0 & 1 \\ -1 & 0\end{matrix}\right]*\left(\begin{matrix}8 \\ 4\end{matrix}\right)\]\[\left(\begin{matrix}0*8+(-1)*4 \\ (-1)*8+0*4\end{matrix}\right)\]we get \[\left(\begin{matrix}-4 \\ -8\end{matrix}\right)\]as the image of V
anonymous
  • anonymous
Ah, I see. Do you think you can help with scale factor with matrices as well?
LynFran
  • LynFran
ok
anonymous
  • anonymous
So this is my question. http://prntscr.com/8g302o I got A, but I was just guessing since the others didn't look right, but the points aren't exact, so it's kind of confusing.
anonymous
  • anonymous
Actually I think it's this one! http://prntscr.com/8g30iv
LynFran
  • LynFran
|dw:1442193863405:dw|
LynFran
  • LynFran
ok so w(-1, 2).. z(-2, -4)...x(5,5)...y(5,3)
LynFran
  • LynFran
its images is being multiple by 3
LynFran
  • LynFran
so for image w we get 3(-1, 2) which give (-3, 6)
anonymous
  • anonymous
Ahh, so that's how you multiply it, thanks a lot.
LynFran
  • LynFran
yep|dw:1442194345221:dw|are the coordinates of image
anonymous
  • anonymous
Okay, I understand now.

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