clamin
  • clamin
Please help!! Medal!! Find the 500th term of the sequence below. 24,30,36,42,48,.... a.3018 b.3024 c.3042 d.2994
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
the first term is 24.the next term is 24+6. so common difference is 6. then use this formula to find the 500th term.\[a_{n}=a _{1}+(n-1)d\]
clamin
  • clamin
an=a1 +(n-1) 6
clamin
  • clamin
B

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
an=24+499*6
clamin
  • clamin
How did u get 499?? @amirreza1870
anonymous
  • anonymous
your n is 500 so n-1 is 499.
clamin
  • clamin
Does it always to be subtract 1? @amirreza1870
anonymous
  • anonymous
ye.s if you want to find 150th (n) term of your arithmetic sequence you should multiply common difference by 149 (n-1) and add the value of this multiplication to the first term. an=a1+(n-1)d

Looking for something else?

Not the answer you are looking for? Search for more explanations.