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anonymous
 one year ago
Let A(x)= SUM(a_nX^n) be the generating function of the sequence a_0, a_1, a_2, ... that is recursively defined by a_0=a_1=1 and a_n=3(a_(n1))(a_(n2) where (n>=2). Compute a_5
anonymous
 one year ago
Let A(x)= SUM(a_nX^n) be the generating function of the sequence a_0, a_1, a_2, ... that is recursively defined by a_0=a_1=1 and a_n=3(a_(n1))(a_(n2) where (n>=2). Compute a_5

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you have the rule, and the starting values ... just use them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I knew how to do that I probably would have done that. I have no idea how to do this problem.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2let n=2, what does the rule become?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2a_n = 3 a_(n1)  a_(n2) 2 2 2 a_2 = 3 a_(21)  a_(22) a_2 = 3 a_(1)  a_(0) and we have the values for 0 and 1 already stated ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2then let n=3, then 4, then 5 and you will generate the list of values with each new calculation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I see. I have to write out each one

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2it would help yes .... the process is short enough that it is the most efficient method

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2if youhad to find say a103 then finding a closed form would be more suitable

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2or writing a computer code to work it thru for you :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I still do not think I am doing this correctly. My answer is x+2x^2+5x^3+13x^4+34x^5

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2a_(2) = 3 a_(1)  a_(0) but a_(0) = 1 and a_(1) = 1 so, a_(2) = 3(1)  1 = 2

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2lets forgo the _(n) stuff becuase its a bugger to type a3 = 3 a2  a1, but we know a2 and a1 a3 = 3(2)  1 = 5  a4 = 3 a3  a2, but we know a3 and a2 a4 = 3(5)  2 = 13  a5 = 3 a4  a3, but we know a4 and a3 ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does that mean my generating function is correct?
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