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Pulsified333

  • one year ago

Assume that you have 6 dimes and 4 quarters (all distinct), and you select 3 coins. (1) In how many ways can the selection be made? (2) In how many ways can the selection be made if all the coins are dimes? (3) In how many ways can the selection be made if you select 2 dimes and 1 quarter? (4) In how many ways can the selection be made so that at least 2 coins are dimes?

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  1. rock_mit182
    • one year ago
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    1) C(6,3) or C(4,3)

  2. rock_mit182
    • one year ago
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    @ganeshie8

  3. Pulsified333
    • one year ago
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    so 1)24?

  4. rock_mit182
    • one year ago
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    Im sorry, you're right

  5. rock_mit182
    • one year ago
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    :)

  6. rock_mit182
    • one year ago
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    I was looking at the wrong values

  7. rock_mit182
    • one year ago
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    I think u can figure this out by your own from now

  8. Pulsified333
    • one year ago
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    im right on what?

  9. rock_mit182
    • one year ago
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    on the frist one

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