anonymous
  • anonymous
QUICK QUESTION: what is sqr(y^9)
Mathematics
chestercat
  • chestercat
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Zale101
  • Zale101
|dw:1442209040037:dw|
Jhannybean
  • Jhannybean
\[\large \sqrt{y^9}= (y^9)^{1/2} = y^{9/2} = y^{4}\cdot y^{1/2}=~?\]
anonymous
  • anonymous
how did u get 4 from y^9*1/2? Thats the part im stuck on

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madhu.mukherjee.946
  • madhu.mukherjee.946
subtracted 1/2 from 9/2
anonymous
  • anonymous
so how do I know to subtract 1/2 from the 9/2
madhu.mukherjee.946
  • madhu.mukherjee.946
i would prefer you follow this method |dw:1442209618030:dw|
anonymous
  • anonymous
then im left with y^4 and y right?
madhu.mukherjee.946
  • madhu.mukherjee.946
no u are left with y^4 and y^1/2
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442209728882:dw|
anonymous
  • anonymous
oh ok
madhu.mukherjee.946
  • madhu.mukherjee.946
u get that now?
anonymous
  • anonymous
so then I have y^4 and y^1/2 now I have to add them?
madhu.mukherjee.946
  • madhu.mukherjee.946
yes
madhu.mukherjee.946
  • madhu.mukherjee.946
so what do you get
anonymous
  • anonymous
y^4.5?!?!?!
Jhannybean
  • Jhannybean
you don't add them...
madhu.mukherjee.946
  • madhu.mukherjee.946
thats it
madhu.mukherjee.946
  • madhu.mukherjee.946
|dw:1442210024677:dw|
Jhannybean
  • Jhannybean
You have your simplification already, \(\sf y^4 \cdot y^{1/2}\) \(y^{1/2}\) is written as the square root, therefore.. \[\boxed{\sqrt{y^9} =~ y^4\sqrt{y}} \]
madhu.mukherjee.946
  • madhu.mukherjee.946
same thing but its better not to give the answer in square root form
Jhannybean
  • Jhannybean
So if you understand square roots right, you'll know that for very 2 pairs of terms, only 1 will come out of the square root. therefore if you divide 9 by 1/2, you get 4.5, which is 4 1/2. y^4 means that 4 pairs of y came out of the square root, and you still have 1 left inside. 1 is half of 2, therefore it cannot come out of the square root.
anonymous
  • anonymous
ok so my final answer with this is y^4 and sqr(y)
Jhannybean
  • Jhannybean
Does that make more sense, @Knamzy ? And yes, that is your answer.
anonymous
  • anonymous
ok thank all you guy for the patience, appreciate it
madhu.mukherjee.946
  • madhu.mukherjee.946
your welcome:) its our job thats why we are here!!!!

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