## anonymous one year ago QUICK QUESTION: what is sqr(y^9)

1. Zale101

|dw:1442209040037:dw|

2. Jhannybean

$\large \sqrt{y^9}= (y^9)^{1/2} = y^{9/2} = y^{4}\cdot y^{1/2}=~?$

3. anonymous

how did u get 4 from y^9*1/2? Thats the part im stuck on

subtracted 1/2 from 9/2

5. anonymous

so how do I know to subtract 1/2 from the 9/2

i would prefer you follow this method |dw:1442209618030:dw|

7. anonymous

then im left with y^4 and y right?

no u are left with y^4 and y^1/2

|dw:1442209728882:dw|

10. anonymous

oh ok

u get that now?

12. anonymous

so then I have y^4 and y^1/2 now I have to add them?

yes

so what do you get

15. anonymous

y^4.5?!?!?!

16. Jhannybean

thats it

|dw:1442210024677:dw|

19. Jhannybean

You have your simplification already, $$\sf y^4 \cdot y^{1/2}$$ $$y^{1/2}$$ is written as the square root, therefore.. $\boxed{\sqrt{y^9} =~ y^4\sqrt{y}}$

same thing but its better not to give the answer in square root form

21. Jhannybean

So if you understand square roots right, you'll know that for very 2 pairs of terms, only 1 will come out of the square root. therefore if you divide 9 by 1/2, you get 4.5, which is 4 1/2. y^4 means that 4 pairs of y came out of the square root, and you still have 1 left inside. 1 is half of 2, therefore it cannot come out of the square root.

22. anonymous

ok so my final answer with this is y^4 and sqr(y)

23. Jhannybean

Does that make more sense, @Knamzy ? And yes, that is your answer.

24. anonymous

ok thank all you guy for the patience, appreciate it