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anonymous
 one year ago
Join (x27)/(x^(1/3)3)
anonymous
 one year ago
Join (x27)/(x^(1/3)3)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know what that means, I was hoping someone would. But I googled it and all it took me to was to joining fraction. A website gave me this answer\[x ^{2/3}+3\sqrt[3]{x}+9\] but I don't know how they got there

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0hmm I'll type it out in a more readable format first then\[\frac{\left(x27\right)}{\left(x^{\frac{1}{3}}3\right)}\]is this right?

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Okay... do you know how to simplify the exponent 1/3 of the bottom portion?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i tried multiplying by the bottom conjugate but i got very lost.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0https://www.mathsisfun.com/algebra/exponentfractional.html Have you tried this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i went on the page and i get the information, I just don't get how to tie it in with the problem

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Well let's convert the x^(1/3) first.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0\[x^{\frac{a}{b}}=\sqrt[b]{x^{a}}\]\[x^{\frac{1}{3}}=\sqrt[3]{x^{1}}\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Okay so now we have\[\frac{(x27)}{\sqrt[3]{x}3}\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm, does this help? http://openstudy.com/study#/updates/4e735b990b8b247045d029a1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the problem is \[(x27)\div(\sqrt[3]{x}3)\] but it simplifies to \[\sqrt[3]{x}^{2}+3\sqrt[3]{x}+9\], i dont understand how to simplify it

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Try the link I posted.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes but i didn't know even without the cubed root with x it qualified as the sum of cube formula

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0http://prntscr.com/8g4uw1 Mathematical terminology of "join": to connect with a straight line or curve. Does this help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the regular cube formula is\[(x3)(x ^{2}+3x+9)\]right what i didn't understand is that you can cube root it so it would turn out to \[(x ^{1/3}3)(x ^{2/3}+x ^{1/3}3+9\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 (Sorry, I'm a tad muddled in the brain here. I may need correcting) From what I can understand they simply substituted the exponent for an x^(1/3)...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes because \[x ^{3}27\] is a perfect cube and i'm assuming that x27 is what it look like when its cubed rooted

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Apparently they found a way to use exponent 1/3 to make the process easier.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{x27}{\sqrt[3]{x}3}\rightarrow\frac{x^{1/3}3{x^{1/3}+3x^{1/3}+9}}{\sqrt[3]{x}3}\]...I think I messed up somewhere.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you dont distribute it, you would cancel then \[x ^{1/3}3\] from the top and bottom

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be \[((x ^{1/3}3)(x ^{2/3}+(3timesx ^{1/3})+9)div(x ^{1/3}3)\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0Sorry my mom was cussing me out for being on OS helping people with math ^^;

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.0It may be worth noting that \[\sqrt[3]{27}=3\]Reason:\[27=3\times3\times3\]I'm stuck here, sorry. Maybe ask @ganeshie8 for help e_e!
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