I need someone who can help me understand how to solve Series.I have an exam tommorow,so any help would be much appreciated :)

- anonymous

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- anonymous

\[\sum_{\infty}^{1}\frac{ n }{ n ^{2} +1}\]

- anonymous

Thank you for calling backup :D

- anonymous

@ayeshaafzal221

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## More answers

- anonymous

do u want to learn basic of series ?

- anonymous

Yes

- anonymous

ok :) give me one minute

- anonymous

Sure ^^

- anonymous

ok so there is two types of series one is infinite which is set of positive numbers and keeps going on theres no stop to it
a1, a2 , a3 ,......
then second type is finite which means limited amount of numbers are in that sequence.

- anonymous

I have to learn the infinite ones

- anonymous

Like the one I posted above

- anonymous

ok can u show me some example of what kind of question you will be getting so i want to know which level u are at , if you dont mind.

- anonymous

Sure

- anonymous

##### 1 Attachment

- anonymous

I choose the ones that looked easier for me to understand and put them in that .jpg

- anonymous

I would like to solve them one by one so I can understand them

- anonymous

u know how to take limits right?

- anonymous

kinda

- anonymous

i just learned the basic with another nice guy from this site :D

- anonymous

ok its quite easy basically you take the limit and divide each variable of question with biggest value it ll be mor clear once i solve the question

- anonymous

\[\sum_{\infty}^{1}\frac{ n }{ n ^{2}+1 }\]

- anonymous

i divide with n^2?

- anonymous

yes

- anonymous

but take the limit first like \[\lim_{n \rightarrow \infty} \frac{ n }{ n ^{2} +1}\]

- anonymous

\[\lim_{n \rightarrow \infty }\frac{ \frac{ n }{n ^{2}} }{ \frac{ n ^{2} }{ n ^{2} } +1}\]

- anonymous

like this?

- anonymous

yes :)

- anonymous

And now?

- anonymous

now you cross out the like terms

- IrishBoy123

this might help out
http://www.math.hawaii.edu/~ralph/Classes/242/SeriesConvTests.pdf

- anonymous

If I cross out the like terms,wouldn't it lead me to the exact ecuation with which we started?

- anonymous

no it will be \[\frac{ 0 }{ 1+1 } =0\]

- anonymous

Ohh,I see

- anonymous

I got it

- anonymous

\[\frac{ 0 }{ 1+0 } =0\]

- anonymous

it is infinite/infinite ^ 2 = 0 because infinite ^ 2 is bigger

- anonymous

and infinite ^ 2 / infinite ^ 2 = 1 because it is the same?

- anonymous

yes

- anonymous

do u know what convergent and divergent means?

- anonymous

something that has to do with the result being higher or lower than 1

- anonymous

yes now can u go to this website it has everything you need to know , go through and message me if you dont understand a thing its with examples and solution

- anonymous

http://tutorial.math.lamar.edu/Classes/CalcII/ConvergenceOfSeries.aspx

- anonymous

Thank you :)

- anonymous

dont get scared of first thing scroll down

- anonymous

your welcome :0

- anonymous

:)*

- anonymous

google khan academy geometric series , its a life saver

- anonymous

https://www.khanacademy.org/math/precalculus/seq_induction/infinite-geometric-series/v/infinite-geometric-series

- anonymous

make a free login

- anonymous

I will try to start solve the exercises to see if I can,when I''m stuck I will write the exercise here

- anonymous

Jhanny

- anonymous

You there?

- anonymous

\[\sum_{\infty}^{1}\frac{ n^{2} }{2^{n} }\]

- anonymous

anyone can help me solve this?

- IrishBoy123

put it in a new thread

- anonymous

ok

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