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anonymous

  • one year ago

I need someone who can help me understand how to solve Series.I have an exam tommorow,so any help would be much appreciated :)

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  1. anonymous
    • one year ago
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    \[\sum_{\infty}^{1}\frac{ n }{ n ^{2} +1}\]

  2. anonymous
    • one year ago
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    Thank you for calling backup :D

  3. anonymous
    • one year ago
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    @ayeshaafzal221

  4. anonymous
    • one year ago
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    do u want to learn basic of series ?

  5. anonymous
    • one year ago
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    Yes

  6. anonymous
    • one year ago
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    ok :) give me one minute

  7. anonymous
    • one year ago
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    Sure ^^

  8. anonymous
    • one year ago
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    ok so there is two types of series one is infinite which is set of positive numbers and keeps going on theres no stop to it a1, a2 , a3 ,...... then second type is finite which means limited amount of numbers are in that sequence.

  9. anonymous
    • one year ago
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    I have to learn the infinite ones

  10. anonymous
    • one year ago
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    Like the one I posted above

  11. anonymous
    • one year ago
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    ok can u show me some example of what kind of question you will be getting so i want to know which level u are at , if you dont mind.

  12. anonymous
    • one year ago
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    Sure

  13. anonymous
    • one year ago
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    1 Attachment
  14. anonymous
    • one year ago
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    I choose the ones that looked easier for me to understand and put them in that .jpg

  15. anonymous
    • one year ago
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    I would like to solve them one by one so I can understand them

  16. anonymous
    • one year ago
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    u know how to take limits right?

  17. anonymous
    • one year ago
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    kinda

  18. anonymous
    • one year ago
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    i just learned the basic with another nice guy from this site :D

  19. anonymous
    • one year ago
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    ok its quite easy basically you take the limit and divide each variable of question with biggest value it ll be mor clear once i solve the question

  20. anonymous
    • one year ago
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    \[\sum_{\infty}^{1}\frac{ n }{ n ^{2}+1 }\]

  21. anonymous
    • one year ago
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    i divide with n^2?

  22. anonymous
    • one year ago
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    yes

  23. anonymous
    • one year ago
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    but take the limit first like \[\lim_{n \rightarrow \infty} \frac{ n }{ n ^{2} +1}\]

  24. anonymous
    • one year ago
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    \[\lim_{n \rightarrow \infty }\frac{ \frac{ n }{n ^{2}} }{ \frac{ n ^{2} }{ n ^{2} } +1}\]

  25. anonymous
    • one year ago
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    like this?

  26. anonymous
    • one year ago
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    yes :)

  27. anonymous
    • one year ago
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    And now?

  28. anonymous
    • one year ago
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    now you cross out the like terms

  29. IrishBoy123
    • one year ago
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    this might help out http://www.math.hawaii.edu/~ralph/Classes/242/SeriesConvTests.pdf

  30. anonymous
    • one year ago
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    If I cross out the like terms,wouldn't it lead me to the exact ecuation with which we started?

  31. anonymous
    • one year ago
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    no it will be \[\frac{ 0 }{ 1+1 } =0\]

  32. anonymous
    • one year ago
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    Ohh,I see

  33. anonymous
    • one year ago
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    I got it

  34. anonymous
    • one year ago
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    \[\frac{ 0 }{ 1+0 } =0\]

  35. anonymous
    • one year ago
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    it is infinite/infinite ^ 2 = 0 because infinite ^ 2 is bigger

  36. anonymous
    • one year ago
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    and infinite ^ 2 / infinite ^ 2 = 1 because it is the same?

  37. anonymous
    • one year ago
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    yes

  38. anonymous
    • one year ago
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    do u know what convergent and divergent means?

  39. anonymous
    • one year ago
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    something that has to do with the result being higher or lower than 1

  40. anonymous
    • one year ago
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    yes now can u go to this website it has everything you need to know , go through and message me if you dont understand a thing its with examples and solution

  41. anonymous
    • one year ago
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    http://tutorial.math.lamar.edu/Classes/CalcII/ConvergenceOfSeries.aspx

  42. anonymous
    • one year ago
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    Thank you :)

  43. anonymous
    • one year ago
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    dont get scared of first thing scroll down

  44. anonymous
    • one year ago
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    your welcome :0

  45. anonymous
    • one year ago
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    :)*

  46. anonymous
    • one year ago
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    google khan academy geometric series , its a life saver

  47. anonymous
    • one year ago
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    make a free login

  48. anonymous
    • one year ago
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    I will try to start solve the exercises to see if I can,when I''m stuck I will write the exercise here

  49. anonymous
    • one year ago
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    Jhanny

  50. anonymous
    • one year ago
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    You there?

  51. anonymous
    • one year ago
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    \[\sum_{\infty}^{1}\frac{ n^{2} }{2^{n} }\]

  52. anonymous
    • one year ago
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    anyone can help me solve this?

  53. IrishBoy123
    • one year ago
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    put it in a new thread

  54. anonymous
    • one year ago
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    ok

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