anonymous
  • anonymous
I need someone who can help me understand how to solve Series.I have an exam tommorow,so any help would be much appreciated :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\sum_{\infty}^{1}\frac{ n }{ n ^{2} +1}\]
anonymous
  • anonymous
Thank you for calling backup :D
anonymous
  • anonymous
@ayeshaafzal221

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anonymous
  • anonymous
do u want to learn basic of series ?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
ok :) give me one minute
anonymous
  • anonymous
Sure ^^
anonymous
  • anonymous
ok so there is two types of series one is infinite which is set of positive numbers and keeps going on theres no stop to it a1, a2 , a3 ,...... then second type is finite which means limited amount of numbers are in that sequence.
anonymous
  • anonymous
I have to learn the infinite ones
anonymous
  • anonymous
Like the one I posted above
anonymous
  • anonymous
ok can u show me some example of what kind of question you will be getting so i want to know which level u are at , if you dont mind.
anonymous
  • anonymous
Sure
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
I choose the ones that looked easier for me to understand and put them in that .jpg
anonymous
  • anonymous
I would like to solve them one by one so I can understand them
anonymous
  • anonymous
u know how to take limits right?
anonymous
  • anonymous
kinda
anonymous
  • anonymous
i just learned the basic with another nice guy from this site :D
anonymous
  • anonymous
ok its quite easy basically you take the limit and divide each variable of question with biggest value it ll be mor clear once i solve the question
anonymous
  • anonymous
\[\sum_{\infty}^{1}\frac{ n }{ n ^{2}+1 }\]
anonymous
  • anonymous
i divide with n^2?
anonymous
  • anonymous
yes
anonymous
  • anonymous
but take the limit first like \[\lim_{n \rightarrow \infty} \frac{ n }{ n ^{2} +1}\]
anonymous
  • anonymous
\[\lim_{n \rightarrow \infty }\frac{ \frac{ n }{n ^{2}} }{ \frac{ n ^{2} }{ n ^{2} } +1}\]
anonymous
  • anonymous
like this?
anonymous
  • anonymous
yes :)
anonymous
  • anonymous
And now?
anonymous
  • anonymous
now you cross out the like terms
IrishBoy123
  • IrishBoy123
this might help out http://www.math.hawaii.edu/~ralph/Classes/242/SeriesConvTests.pdf
anonymous
  • anonymous
If I cross out the like terms,wouldn't it lead me to the exact ecuation with which we started?
anonymous
  • anonymous
no it will be \[\frac{ 0 }{ 1+1 } =0\]
anonymous
  • anonymous
Ohh,I see
anonymous
  • anonymous
I got it
anonymous
  • anonymous
\[\frac{ 0 }{ 1+0 } =0\]
anonymous
  • anonymous
it is infinite/infinite ^ 2 = 0 because infinite ^ 2 is bigger
anonymous
  • anonymous
and infinite ^ 2 / infinite ^ 2 = 1 because it is the same?
anonymous
  • anonymous
yes
anonymous
  • anonymous
do u know what convergent and divergent means?
anonymous
  • anonymous
something that has to do with the result being higher or lower than 1
anonymous
  • anonymous
yes now can u go to this website it has everything you need to know , go through and message me if you dont understand a thing its with examples and solution
anonymous
  • anonymous
http://tutorial.math.lamar.edu/Classes/CalcII/ConvergenceOfSeries.aspx
anonymous
  • anonymous
Thank you :)
anonymous
  • anonymous
dont get scared of first thing scroll down
anonymous
  • anonymous
your welcome :0
anonymous
  • anonymous
:)*
anonymous
  • anonymous
google khan academy geometric series , its a life saver
anonymous
  • anonymous
https://www.khanacademy.org/math/precalculus/seq_induction/infinite-geometric-series/v/infinite-geometric-series
anonymous
  • anonymous
make a free login
anonymous
  • anonymous
I will try to start solve the exercises to see if I can,when I''m stuck I will write the exercise here
anonymous
  • anonymous
Jhanny
anonymous
  • anonymous
You there?
anonymous
  • anonymous
\[\sum_{\infty}^{1}\frac{ n^{2} }{2^{n} }\]
anonymous
  • anonymous
anyone can help me solve this?
IrishBoy123
  • IrishBoy123
put it in a new thread
anonymous
  • anonymous
ok

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