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anonymous
 one year ago
hey guys hope your well ! so I have this evaluating proof problem ,can anyone help me plzzz. Its geometric series , question is : suppose m and k are integers with m<k find a formula for evaluating the sum.
anonymous
 one year ago
hey guys hope your well ! so I have this evaluating proof problem ,can anyone help me plzzz. Its geometric series , question is : suppose m and k are integers with m<k find a formula for evaluating the sum.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=m}^{k} ar ^{n}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[S(n) = \frac{ a _{1}(1r) }{ 1r }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know this formula will drive the same way this formula did ^ but just dont know how to set up ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 mind helping?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3for first n terms you have \[\large \Sigma_{k=0}^{n1} \ a \ r^k = a \frac{1r^n}{1r}\]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3so you can calculate 2 summations, each starting at zero and ending somewhere that leaves you with the interval you want to sum over a bit like S(8 to 10) = S(10)  S(7)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3so methodically plug into that formula and see where you go

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3ouch, you are using k and m in your problem so i have removed them to make it cleaner: \[\large \Sigma_{i=0}^{n1} \ a \ r^i = a \frac{1r^n}{1r}\]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.3i mean......i have replaced the k by i
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