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anonymous
 one year ago
Write the partial fraction decomposition of the rational expression.
anonymous
 one year ago
Write the partial fraction decomposition of the rational expression.

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.0know how to start?? \(\large \dfrac{A}{x}+\dfrac{B}{x2}+\dfrac{C}{x4}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0partial fraction decomposition of your expression. once you find A,B,C you're done

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \dfrac{18x^2 68x+24}{x(x2)(x4)} = \dfrac{A}{x}+\dfrac{B}{x2}+\dfrac{C}{x4}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0now simplify the right side, so that it has one common denominator

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0like 1/a + 1/b = (b+a)/ab

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0let me give you a start denominator = x(x2)(x4) numerator = A (x2)(x4) + B.................

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0have you solved a similar problem before?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i just srted this class

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0too early to take that example then

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0start with something easier \(\dfrac{2x+3}{(x+1)(x+2)} \)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0to decompose that into partial fractions means, we need to have fractions with linear denominators \(\dfrac{2x+3}{(x+1)(x+2)} = \dfrac{A}{(x+1)}+\dfrac{B}{(x+2)}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0then find A,B with any method that you prefer. I tried to discuss One of the method earlier

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0taking a common denominator on right side \(\dfrac{A}{(x+1)}+\dfrac{B}{(x+2)} = \dfrac{A(x+1)+B(x+2)}{(x+1)(x+2)}\) makes sense?
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