anonymous
  • anonymous
Friends out there.... HELP!!! Please help me with this one:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
@ganeshie8 please help me. :) @mathmate please help me. :)
rishavraj
  • rishavraj
wht do u think??? @itsmeeQUENNIE i first of all used substitution and then used the ILATE rule.. and thts lengthy

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More answers

anonymous
  • anonymous
i think ...i will use the LIATHE.. and yeah.. you're right.. it's lengthy...
rishavraj
  • rishavraj
the suppose e^x = u so e^x dx = du dx = du/(e^x)
rishavraj
  • rishavraj
use these substitution
anonymous
  • anonymous
why you use first the exponential form?
rishavraj
  • rishavraj
i didn't get tht....wht do u mean???
anonymous
  • anonymous
why you let u = e^x, instead of letting u = cos e^-x ... it is in the rule, right? the LIATHE!
rishavraj
  • rishavraj
u can even apply e^x = u so cos(e^{-x}) = cos(1/u) so the integral would be \[\int\limits u^3 \cos(\frac{ 1 }{ u }) du\]
rishavraj
  • rishavraj
And @itsmeeQUENNIE tbh thanks for postng this creepy question..... made me recall whole chapter :)
anonymous
  • anonymous
hihih.. you're welcome. :)
anonymous
  • anonymous
btw.. i'll try to use your solution...
rishavraj
  • rishavraj
go on....... :) i got the the answer though ....its damn creepy :P
anonymous
  • anonymous
really? hmm.. wait.. :)
rishavraj
  • rishavraj
okay :) take ur time :P
rishavraj
  • rishavraj
@itsmeeQUENNIE u know about using ILATE ??
anonymous
  • anonymous
hey! will i use integration by part>???
anonymous
  • anonymous
yes.. i know that thing. :)
anonymous
  • anonymous
@rishavraj hey! i don't know what to do. :(
rishavraj
  • rishavraj
go for integration by parts :)
anonymous
  • anonymous
let v = u^3 dv = 3u^2du dw = cos (1/u) du w = ???? --> i don't know the answer. :3
rishavraj
  • rishavraj
hold on the integral is \[\int\limits u^3 \cos \frac{ 1 }{ u } du\] first function is u^3 and second function is cos(1/u)
anonymous
  • anonymous
yes.. then?
rishavraj
  • rishavraj
see \[\int\limits u~v ~~dx = u~(\int\limits~v~dx) - \int\limits ({\frac{ du }{ dx } \int\limits v~dx}) ~dx\]
rishavraj
  • rishavraj
u is the first function and v is the second function
rishavraj
  • rishavraj
in ur question u = u^3 and v = cos (1/u)
anonymous
  • anonymous
uhh.. okay... then???
rishavraj
  • rishavraj
now wht...just step further ...hold on i m uploading a pic...might be useful
anonymous
  • anonymous
my head is aching. waah! how to use the LIATHE again???
rishavraj
  • rishavraj
i think LIATHE is same as ILATE
anonymous
  • anonymous
when i was in 2nd yr college... my prof taught the LIATHE in my integral calculus subject... L - for logarithmic, I - for inverse, A - for algebraic, T - for trigonometric, H - for hyperbolic and E - for exponential...
anonymous
  • anonymous
:(
anonymous
  • anonymous
haaay. :( hopeless...
rishavraj
  • rishavraj
yup same except the hyperbolic one :P
anonymous
  • anonymous
@ganeshie8 hey! please teach me on this one.. pretty please???
rishavraj
  • rishavraj
and i went to hav dinner ...so
rishavraj
  • rishavraj
so apply tht ....its easy .too lengthy though
rishavraj
  • rishavraj
@itsmeeQUENNIE u knowing the significance of LIATHE .wht it is used for??
anonymous
  • anonymous
i don't know how to do that.. it's too complicated for me...
rishavraj
  • rishavraj
see u^3 is first function and cos(1/u) is second so hold on i m gonna upload a pic
rishavraj
  • rishavraj
@itsmeeQUENNIE

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