A community for students.
Here's the question you clicked on:
 0 viewing
mathmath333
 one year ago
Their are 6 pieces king,queen,rook bishop,knight
and pawn.In how many ways can u arrange them
so that king always comes before queen and queen
always comes before rook?
mathmath333
 one year ago
Their are 6 pieces king,queen,rook bishop,knight and pawn.In how many ways can u arrange them so that king always comes before queen and queen always comes before rook?

This Question is Closed

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} & \normalsize \text{Their are 6 pieces king,queen,rook bishop,knight }\hspace{.33em}\\~\\ & \normalsize \text{and pawn.In how many ways can u arrange them }\hspace{.33em}\\~\\ & \normalsize \text{so that king always comes before queen and queen }\hspace{.33em}\\~\\ & \normalsize \text{always comes before rook? }\hspace{.33em}\\~\\ \end{align}}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4_K_Q_R_ 4 ways to put the bishop 5 ways to put the knight 6 ways to put the pawn. 120 ways. Would that be right?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1what about this cases KQR   KQR  K Q  R

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4_K_Q_R_ Say put the biship after R then we have _K_Q_R_B_ that's why 5 places for knight. Say _K_Q_R_B_N_ and the pawn chooses to be last, then _K_Q_R_B_N_P_ (if there is a seventh) so that gives the case KQR___ similarly for other situations.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4Or, another way to look at it, it would be 6! ways in general, but we will tag the 3! arrangements of KQR and use only one, so the result would be 6!/3! as you had it. This is a combinatorial verification!

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1what about the question u posted yesterday :)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1http://openstudy.com/users/mathmath333#/updates/55f52326e4b0cf7fa75bbeb9

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1I made a conclusion if such question comes in exam i will leave it unsolved and move to next easy question

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1:) wise ( ͡° ͜ʖ ͡°) but maybe theres some trick still hidden somewhere :)

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1I will not trust any trick , another conclusion

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4I hope someone will post a smarter and faster solution. Although that one doesn't take long, it looks complicated, but detailed for the purpose of explaining only.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1question is closed

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4It's ok. I'll keep looking at my end!

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1I'll ask my prof for a soln

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4@mathmath333 Thank you. Btw, have you done generating functions yet?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1No, this sounds a higher level maths to me. I haven't studied calculus .

mathmate
 one year ago
Best ResponseYou've already chosen the best response.4It's part of combinatorics, NCR (no calculus required). That might be a hint for me where to look though. xD

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1lol i m a newbie in case of math , i only learn things that matters to me
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.