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anonymous

  • one year ago

A 1000-kg car traveling at 66 m/s hits a 2000-kg car at rest and the two travel together after the collision. Calculate the speed with which they move.

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  1. anonymous
    • one year ago
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    initial momentum = final momentum \[m_1v_1+m_2v_2=v_f(m_1+m_2)\]

  2. anonymous
    • one year ago
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    so 1000x2000 +2000x v2 =vf(3000) ???

  3. anonymous
    • one year ago
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    No, pair the masses and velocities. So 1000 kg goes with 66 m/s and 2000 kg goes with 0 m/s (since the car is at rest) \[(1000~kg)(66~m/s)+(2000~kg)(0~m/s)=v_f(2000~kg+1000~kg)\]

  4. anonymous
    • one year ago
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    so the only variable left if \(v_f\)

  5. anonymous
    • one year ago
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    so its 68000/3000 which equals 22.66 right ?

  6. anonymous
    • one year ago
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    2000*0=0, so 66,000/3,000 = 22 m/s even

  7. anonymous
    • one year ago
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    Thank you very much !!

  8. anonymous
    • one year ago
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    you're welcome

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